Dav*_*rry 8 c++ lookup-tables constexpr c++14
我试图基于一个整数数组创建一个简单的 LookUpTable,其思路是在编译时计算它.
试图使它可以用于我可能拥有的各种整数类型的任何其他未来表,我需要它作为模板.
所以我有一个LookUpTable.h
#ifndef LOOKUPTABLE_H
#define LOOKUPTABLE_H
#include <stdexcept> // out_of_range
template <typename T, std::size_t NUMBER_OF_ELEMENTS>
class LookUpTableIndexed
{
private:
//constexpr static std::size_t NUMBER_OF_ELEMENTS = N;
// LookUpTable
T m_lut[ NUMBER_OF_ELEMENTS ] {}; // ESSENTIAL T Default Constructor for COMPILE-TIME INTERPRETER!
public:
// Construct and Populate the LookUpTable such that;
// INDICES of values are MAPPED to the DATA values stored
constexpr LookUpTableIndexed() : m_lut {}
{
//ctor
}
// Returns the number of values stored
constexpr std::size_t size() const {return NUMBER_OF_ELEMENTS;}
// Returns the DATA value at the given INDEX
constexpr T& operator[](std::size_t n)
{
if (n < NUMBER_OF_ELEMENTS)
return m_lut[n];
else throw std::out_of_range("LookUpTableIndexed[] : OutOfRange!");
}
constexpr const T& operator[](std::size_t n) const
{
if (n < NUMBER_OF_ELEMENTS)
return m_lut[n];
else throw std::out_of_range("LookUpTableIndexed[] const : OutOfRange!");
}
using iterator = T*;
// Returns beginning and end of LookUpTable
constexpr iterator begin() {return &m_lut[0 ];}
constexpr iterator end () {return &m_lut[NUMBER_OF_ELEMENTS];}
};
#endif // LOOKUPTABLE_H
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我试图在一个类中使用它来快速衰减一个整数距离的整数信号.
例如.这只是Foo.h的示例用法
#ifndef FOO_H
#define FOO_H
#include <limits> // max, digits
#include <stdlib.h> // abs
#include "LookUpTable.h" // LookUpTableIndexed
class Foo
{
private:
template <typename TDistance,
TDistance MAXIMUM_DISTANCE,
std::size_t NUMBER_OF_DIGITS>
struct DistanceAttenuation
{
private:
// Maximum value that can be held in this type
//constexpr auto MAXIMUM_DISTANCE = std::numeric_limits<TDistance>::max();
// Number of bits used by this type
//constexpr auto NUMBER_OF_DIGITS = std::numeric_limits<TDistance>::digits;
// LookUpTable
LookUpTableIndexed<TDistance, NUMBER_OF_DIGITS> m_attenuationRangeUpperLimit {}; // ESSENTIAL LookUpTable Default Constructor for COMPILE-TIME INTERPRETER!
// Returns the number of bits to BIT-SHIFT-RIGHT, attenuate, some signal
// given its distance from source
constexpr std::size_t attenuateBy(const TDistance distance)
{
for (std::size_t i {NUMBER_OF_DIGITS}; (i > 0); --i)
{
// While distance exceeds upper-limit, keep trying values
if (distance >= m_attenuationRangeUpperLimit[i - 1])
{
// Found RANGE the given distance occupies
return (i - 1);
}
}
throw std::logic_error("DistanceAttenuation::attenuateBy(Cannot attenuate signal using given distance!)");
}
public:
// Calculate the distance correction factors for signals
// so they can be attenuated to emulate the the effects of distance on signal strength
// ...USING THE INVERSE SQUARE RELATIONSHIP OF DISTANCE TO SIGNAL STRENGTH
constexpr DistanceAttenuation() : m_attenuationRangeUpperLimit {}
{
//ctor
// Populate the LookUpTable
for (std::size_t i {0}; (i < NUMBER_OF_DIGITS); ++i)
{
TDistance goo = 0; // Not an attenuation calculation
TDistance hoo = 0; // **FOR TEST ONLY!**
m_attenuationRangeUpperLimit[i] = MAXIMUM_DISTANCE - goo - hoo;
}
static_assert((m_attenuationRangeUpperLimit[0] == MAXIMUM_DISTANCE),
"DistanceAttenuation : Failed to Build LUT!");
}
// Attenuate the signal, s, by the effect of the distance
// by some factor, a, where;
// Positive contribution values are attenuated DOWN toward ZERO
// Negative UP ZERO
constexpr signed int attenuateSignal(const signed int s, const int a)
{
return (s < 0)? -(abs(s) >> a) :
(abs(s) >> a);
}
constexpr signed int attenuateSignalByDistance(const signed int s, const TDistance d)
{
return attenuateSignal(s, attenuateBy(d));
}
};
using SDistance_t = unsigned int;
constexpr static auto m_distanceAttenuation = DistanceAttenuation<SDistance_t,
std::numeric_limits<SDistance_t>::max(),
std::numeric_limits<SDistance_t>::digits>();
public:
Foo() {}
~Foo() {}
// Do some integer foo
signed int attenuateFoo(signed int signal, SDistance_t distance) {return m_distanceAttenuation::attenuateSignalByDistance(signal, distance);}
};
#endif // FOO_H
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我尝试过几种方式,使用CppCon 2015的youtube视频教程:Scott Schurr"constexpr:Applications"和其他人,但它不会编译给出错误;
error: 'constexpr static auto m_distanceAttenuation...' used before its definition
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而静态断言失败了
error: non-constant condition for static assertion
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表明它在编译时没有计算任何东西.
我是C++的新手.
我知道我做的事情很明显,但我不知道它是什么.
我滥用静态还是constexpr?
numeric_limits是constexpr?
我究竟做错了什么?谢谢.
一些观察
1)正如 michalsrb 所观察到的,当您初始化并且是 的一部分时,Foo它并不完整,因此是不完整的。m_distanceAttenuationDistanceAttenuationFoo
不幸的是,您无法初始化static constexpr具有不完整类型的成员(如本答案中jogojapan 更好地解释的那样)。
建议:DistanceAttenuation在外部(和之前)定义它Foo;所以它是一个完整的类型,可以用来初始化m_distanceAttenuation;就像是
template <typename TDistance,
TDistance MAXIMUM_DISTANCE,
std::size_t NUMBER_OF_DIGITS>
struct DistanceAttenuation
{
// ...
};
class Foo
{
// ...
};
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2) 在C++14中,constexpr方法不是const方法;建议:也定义以下方法,const否则不能在某些constexpr表达式中使用它们
constexpr std::size_t attenuateBy (const TDistance distance) const
constexpr signed int attenuateSignal(const signed int s, const int a) const
constexpr signed int attenuateSignalByDistance(const signed int s, const TDistance d) const
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3) 在 中attenuateBy(),以下测试for永远为真
for (std::size_t i {NUMBER_OF_DIGITS - 1}; (i >= 0); --i)
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因为 astd::size_t是ever >= 0,所以for进入循环并且永远不会退出;建议:重新定义i为intorlong
4)在attenuateFoo()您使用m_DistanceAttenuation变量定义为的地方m_distanceAttenuation;建议:所用变量的正确名称
5)在您使用运算符attenuateFoo()调用方法时;建议:使用运算符,所以(也考虑第(4)点)attenuateSignalByDistance()::.
signed int attenuateFoo(signed int signal, SDistance_t distance)
{return m_distanceAttenuation.attenuateSignalByDistance(signal, distance);}
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