单击按钮离子2时更改图标

Question

我正在尝试更改图标时单击按钮显示隐藏的内容我需要更改上下箭头图标

<button clear text-center (click)="toggle()">
 <ion-icon name="arrow-dropdown-circle"></ion-icon>
 </button>

<ion-col [hidden]="!visible" class="accountBalance animated slideInUp">
       <ion-list>
          <ion-item>
            <h3>limit</h3>
                <ion-note item-right>
                    <h2>&#x20B9; 55000.00</h2>
                </ion-note>
          </ion-item>
<ion-list></ion-col>

file.ts

visible = false;
  toggle() {
   this.visible = !this.visible;
  }

Answer 1

你可以*ngIf在这里使用指令来显示条件图标.

<button clear text-center (click)="toggle()">
   <ion-icon name="arrow-drop down-circle" *ngIf="!visible"></ion-icon>
   <ion-icon name="arrow-drop up-circle" *ngIf="visible"></ion-icon>
</button>

您可以使用name属性而不是创建两个不同的ion-icon

<button clear text-center (click)="toggle()">
   <ion-icon 
       [name]="visible ? 'arrow-drop up-circle' :'arrow-drop down-circle'">
   </ion-icon>
</button>

Answer 2

您可以在name=属性中创建条件

<ion-icon [name]="visible ? 'arrow-dropdown' : 'arrow-dropup'"></ion-icon>