如何将多个动态行插入数据库

Question

我有一个使用php和jQuery创建的多行动态表.这是查看表格的链接.

一切正常,除非我将数据插入数据库,序列号不会按顺序保存.我的插入查询如下:

for($i = 0; $i < count($_POST['C_Objectives']); $i++)
{
    $sql = "INSERT INTO Appraisal_Objectives (Serial_Number,Objectives,Measures,Targets,subtotal,Corporate_Objective,Row_Number,ID) Values ('$formno','||<==','==','==','".$_POST['SubTotals'][$i]."','".$_POST['C_Objectives'][$i]."','".$_POST['SNo'][$i]."','$statement')";
    $stmt = sqlsrv_query($conn, $sql);
    if($stmt === false)
        die(print_r(sqlsrv_errors(), true));
    else
        echo " ";
}

for($i = 0; $i < count($_POST['Measures']); $i++)
{
    $sql = "INSERT INTO Appraisal_Objectives (Serial_Number,Objectives,Measures,Targets,Weightage,Row_Number,target_date,ID) VALUES ('$formno','".$_POST['Objectives'][$i]."','".$_POST['Measures'][$i]."','".$_POST['Achievement'][$i]."','".$_POST['Weightage_Target'][$i]."','".$_POST['SNo'][$i]."','".$_POST['Date_Target'][$i]."','$statement')"; 
    $stmt = sqlsrv_query($conn, $sql);
    if($stmt === false)
        die(print_r(sqlsrv_errors(), true));
    else
        echo " ";
}

序列号保存在Row_Number$_POST['SNo'][$i]列中,使用.是否可以使用1个插入查询保存两个动态行,以便顺序保存序列号？

这是$_POST数组结果:

    [Row_Number] => Array
        (
            [0] => 1
            [1] => 2
        )

    [C_Objectives] => Array
        (
            [0] => A
            [1] => B
        )

    [Objectives] => Array
        (
            [0] => a1
            [1] => a4
            [2] => a7
            [3] => b1
        )

    [Measures] => Array
        (
            [0] => a2
            [1] => a5
            [2] => a8
            [3] => b2
        )

    [Achievement] => Array
        (
            [0] => a3
            [1] => a6
            [2] => a9
            [3] => b3
        )

    [Date_Target] => Array
        (
            [0] => 2016-09-09
            [1] => 2016-09-09
            [2] => 2016-09-09
            [3] => 2016-09-09
        )

    [Weightage_Target] => Array
        (
            [0] => 25
            [1] => 25
            [2] => 25
            [3] => 25
        )

    [SNo] => Array
        (
            [0] => 3
            [1] => 4
            [2] => 5
            [3] => 6
        )

    [SubTotals] => Array
        (
            [0] => 75
            [1] => 25
        )

    [GrandTotal] => 100
)

我也尝试使列自动递增,但是不会以与在前端输入的顺序相同的顺序保存数据.

Answer 1

您的插入有性能问题.请更改插入数据库的方式.您可以在一个查询中执行所有这些操作.即使你有第一个"for"的20个循环和第二个"for"的20个循环.

回答你问的问题

如果要按$ _POST ['SNo']顺序插入,请更改此行

for($i = 0; $i < count($_POST['C_Objectives']); $i++)

到了

foreach($_POST['SNo'] as $i)

如果您需要一次插入多个,请执行以下操作:

INSERT INTO Appraisal_Objectives (Serial_Number,Objectives,...)
VALUES (Value1,Value2,...), (Value1,Value2,...)

这是你必须做的

在您的代码中,您在6个查询中执行了相同的查询.它甚至可以超过6个更多$ _POST ['Measures']或$ _POST ['C_Objectives']数组长度.您需要将它们放在一个查询中,当您不需要设置该值时,只需将其设置为列默认值即可.例如NULL

像这样的东西:

//first we create $values array. it contains all values that you need to insert to the db
$values = array();
$j=0;

for($i = 0; $i < count($_POST['C_Objectives']); $i++){
    $values[$j]['Serial_Number'] = $formno;
    $values[$j]['Objectives'] = '||<==';
    //and fill others here
    //fill all cols that you wrote inside your query with the correct order
    $j++;
}

for($i = 0; $i < count($_POST['Measures']); $i++){
    $values[$j]['Serial_Number'] = $formno;
    $values[$j]['Objectives'] = $_POST['Objectives'][$i];
    //and fill others here
    //fill all cols that you wrote inside your query with the correct order
    $j++;
}

//now create (value1,value2,...),(value1,value2,...),...
$query = NULL;
foreach($values as $value){
    $tmp = NULL;
    foreach($value as $v){
        $tmp .= ($v=='')? 'NULL,' : "'$v',";
    }
    $tmp = rtrim($tmp,',');
    $query .= "($tmp),";
}
$query = rtrim($query,',');

//Now Insert
$sql = "INSERT INTO Appraisal_Objectives (Serial_Number,Objectives,...) VALUES $query";

在这个例子中,我只是告诉你如何做到这一点.请记住,您必须检查$ v并按列类型进行准备.检查是否$_POST[KEY]已设置且是否为数组.如果$query为空,请不要插入数据库.

您的代码非常重要

如果这不是您的原始代码,则没有问题,但如果是,请更改您在查询中使用$ _POST的方式.它的安全性很低.至少你需要在使用之前验证它们.