bla*_*rno 9 xml orm symfony doctrine-orm
我正在尝试使用Doctrine 2 ORM设置类继承,但是遇到错误(即使遵循他们的示例).我正在使用Symfony 2沙箱中的控制台.这个简单的例子使用Person和Employee类; 一个员工伸出的人.
我在尝试生成实体时遇到的错误是:
[Doctrine\ORM\Mapping\MappingException] Entity class 'Employee' used in the discriminator map of class 'Application\MyBundle\Entity\Person' does not exist.
正在尝试的XML如下:
人
<?xml version="1.0" encoding="utf-8"?>
<doctrine-mapping xmlns="http://doctrine-project.org/schemas/orm/doctrine-mapping"
xsi="http://www.w3.org/2001/XMLSchema-instance"
schemaLocation="http://doctrine-project.org/schemas/orm/doctrine-mapping http://doctrine-project.org/schemas/orm/doctrine-mapping.xsd">
<entity name="Application\MyBundle\Entity\Person" inheritance-type="SINGLE_TABLE">
<change-tracking-policy>DEFERRED_IMPLICIT</change-tracking-policy>
<id name="id" type="integer" column="id">
<generator strategy="AUTO"/>
</id>
<discriminator-column name="discr" type="string" />
<discriminator-map>
<discriminator-mapping value="employee" class="Employee" />
</discriminator-map>
<lifecycle-callbacks/>
</entity>
</doctrine-mapping>
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雇员
<?xml version="1.0" encoding="utf-8"?>
<doctrine-mapping xmlns="http://doctrine-project.org/schemas/orm/doctrine-mapping"
xsi="http://www.w3.org/2001/XMLSchema-instance"
schemaLocation="http://doctrine-project.org/schemas/orm/doctrine-mapping http://doctrine-project.org/schemas/orm/doctrine-mapping.xsd">
<entity name="Application\MyBundle\Entity\Employee">
<change-tracking-policy>DEFERRED_IMPLICIT</change-tracking-policy>
<id name="id" type="integer" column="id">
<generator strategy="AUTO"/>
</id>
<lifecycle-callbacks/>
</entity>
</doctrine-mapping>
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似乎很多人都没有使用XML来配置他们的Doctrine实体(大多数示例都使用PHP注释),但它似乎对我来说最合乎逻辑,所以我想知道如何正确地执行它.有没有其他人有这个问题,或知道解决方案?
完整的异常跟踪如下:
Exception trace: () at C:\SVN\Symfony\symfony-sandbox\src\vendor\doctrine\lib\Doctrine\ORM\Mappi ng\MappingException.php:187 Doctrine\ORM\Mapping\MappingException::invalidClassInDiscriminatorMap() at C:\S VN\Symfony\symfony-sandbox\src\vendor\doctrine\lib\Doctrine\ORM\Mapping\ClassMet adataInfo.php:1465 Doctrine\ORM\Mapping\ClassMetadataInfo->setDiscriminatorMap() at C:\SVN\Symfony \symfony-sandbox\src\vendor\doctrine\lib\Doctrine\ORM\Mapping\Driver\XmlDriver.p hp:98 Doctrine\ORM\Mapping\Driver\XmlDriver->loadMetadataForClass() at C:\SVN\Symfony \symfony-sandbox\src\vendor\doctrine\lib\Doctrine\ORM\Mapping\Driver\DriverChain .php:75 Doctrine\ORM\Mapping\Driver\DriverChain->loadMetadataForClass() at C:\SVN\Symfo ny\symfony-sandbox\src\vendor\doctrine\lib\Doctrine\ORM\Mapping\ClassMetadataFac tory.php:280 Doctrine\ORM\Mapping\ClassMetadataFactory->loadMetadata() at C:\SVN\Symfony\sym fony-sandbox\src\vendor\doctrine\lib\Doctrine\ORM\Mapping\ClassMetadataFactory.p hp:178 Doctrine\ORM\Mapping\ClassMetadataFactory->getMetadataFor() at C:\SVN\Symfony\s ymfony-sandbox\src\vendor\doctrine\lib\Doctrine\ORM\Mapping\ClassMetadataFactory .php:125 Doctrine\ORM\Mapping\ClassMetadataFactory->getAllMetadata() at C:\SVN\Symfony\s ymfony-sandbox\src\vendor\symfony\src\Symfony\Bundle\DoctrineBundle\Command\Doct rineCommand.php:143 Symfony\Bundle\DoctrineBundle\Command\DoctrineCommand->getBundleMetadatas() at C:\SVN\Symfony\symfony-sandbox\src\vendor\symfony\src\Symfony\Bundle\DoctrineBun dle\Command\GenerateEntitiesDoctrineCommand.php:77 Symfony\Bundle\DoctrineBundle\Command\GenerateEntitiesDoctrineCommand->execute( ) at C:\SVN\Symfony\symfony-sandbox\src\vendor\symfony\src\Symfony\Component\Con sole\Command\Command.php:150 Symfony\Component\Console\Command\Command->run() at C:\SVN\Symfony\symfony-sand box\src\vendor\symfony\src\Symfony\Component\Console\Application.php:184 Symfony\Component\Console\Application->doRun() at C:\SVN\Symfony\symfony-sandbo x\src\vendor\symfony\src\Symfony\Bundle\FrameworkBundle\Console\Application.php: 74 Symfony\Bundle\FrameworkBundle\Console\Application->doRun() at C:\SVN\Symfony\s ymfony-sandbox\src\vendor\symfony\src\Symfony\Component\Console\Application.php: 113 Symfony\Component\Console\Application->run() at C:\SVN\Symfony\symfony-sandbox\ app\console:11
我得到了同样的错误.
我想出了该怎么做:
在您的示例中,您必须已生成"员工"实体.
为我工作.
在定义鉴别器时,您可能应该使用完整的类名(带有命名空间)。
喜欢:
<discriminator-map>
<discriminator-mapping value="employee" class="Application\MyBundle\Entity\Employee" />
</discriminator-map>
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