如何在C++中完全释放cv :: Mat的内存

Question

当我尝试创建一个cv :: Mat并在之后发布它(下面的代码)时,我仍然(根据valgrind)内存泄漏大约每个像素1个字节.

有谁知道如何正确释放cv :: Mat的记忆？

谢谢你的激情:)

码:

int main(int argc, char** argv)
{
  cv::Mat* matrx = new cv::Mat(1000,1000,CV_8UC1,0.);
  matrx->release();
  delete matrx;
  return 0;
}

Valgrind的:

[...]
==29420==    1,000,028 bytes in 1 blocks are definitely lost in loss record 372 of 372
==29420==    at 0x4C2AB80: malloc (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==29420==    by 0x5438877: cv::fastMalloc(unsigned long) (in /usr/lib/x86_64-linux-gnu/libopencv_core.so.2.4.8)
==29420==    by 0x536FE2A: cv::Mat::create(int, int const*, int) (in /usr/lib/x86_64-linux-gnu/libopencv_core.so.2.4.8)
==29420==    by 0x426FB5: cv::Mat::create(int, int, int) (mat.inl.hpp:663)
==29420==    by 0x426ECD: cv::Mat::Mat(int, int, int, cv::Scalar_<double> const&) (mat.inl.hpp:347)
==29420==    by 0x425A09: main (main.cpp:18)
==29420== 
==29420== LEAK SUMMARY:
==29420==    definitely lost: 1,000,028 bytes in 1 blocks
==29420==    indirectly lost: 0 bytes in 0 blocks
==29420==      possibly lost: 5,072 bytes in 95 blocks
==29420==    still reachable: 304,758 bytes in 1,348 blocks
==29420==         suppressed: 0 bytes in 0 blocks
[...]

Answer 1

opencv github 的反馈似乎很清楚：您使用 OpenCV 3.x 进行编译，但在运行时使用 OpenCV 2.4.8。由于它们不是二进制兼容的，因此它无法正确释放cv::Mat. 让我们将您的导出LD_LIBRARY_PATH到OCV_DIST/lib用于编译的 OpenCV 3.x。

请注意，如果您使用delete指针，则之前甚至不需要release()。