She*_*ani 3 javascript c# asp.net try-catch
我有以下代码,但没有显示警告框.
try
{
do something..
}
catch(Exception ex)
{
Response.Write("<script>alert('"+ex+"')</script>");
}
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如果我使用此代码,则会出现警告框.
try
{
do some thing
}
catch (Exception ex)
{
Response.Write("<script>alert(\"an error occur\")</script>");
}
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如何在警告框中显示异常变量?
如果要显示堆栈跟踪:
Response.Write("<script>alert('"+ Server.HtmlEncode(ex.ToString()) + "')</script>");
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或者如果你只想要消息
Response.Write("<script>alert('"+ Server.HtmlEncode(ex.Message) + "')</script>");
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