Ami*_*ari 5 android android-fragments rx-java rx-android
我有一个EditText在Activity这里用户可以输入和搜索的东西.在搜索栏下方,我有2个tabs附加到a ViewPager.我为标签EditText中的2 添加了一个RxJava事件更改侦听器Fragments.这是相关代码:
private Subscription subscription;
@Nullable
@Override
public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.fragment_people_search, container, false);
ButterKnife.bind(this, view);
LogUtil.i(TAG, "onCreateView called");
if (getActivity() != null) {
inputSearch = (EditText) getActivity().findViewById(R.id.editText11);
}
return view;
}
@Override
public void onResumeFragment() {
LogUtil.i(TAG, "onResumeFragment called");
if (subscription == null) {
doSearch();
}
}
private void doSearch() {
LogUtil.i(TAG, "doSearch called");
subscription = RxTextView.textChangeEvents(inputSearch)
.debounce(400, TimeUnit.MILLISECONDS)
.map(new Func1<TextViewTextChangeEvent, String>() {
@Override
public String call(TextViewTextChangeEvent textViewTextChangeEvent) {
return textViewTextChangeEvent.text().toString().trim();
}
})
.switchMap(new Func1<String, Observable<SearchUserData>>() {
@Override
public Observable<SearchUserData> call(String s) {
term = s;
if (previousTerm.equalsIgnoreCase(term) && TextUtils.isEmpty(term)) {
//do not reset pagination variables
} else if (!previousTerm.equalsIgnoreCase(term) && TextUtils.isEmpty(term)) {
min = 0;
max = 14;
} else if (previousTerm.equalsIgnoreCase(term) && !TextUtils.isEmpty(term)) {
//do not reset pagination variables
} else {
min = 0;
max = 14;
}
loadMoreOrNot = true;
previousTerm = term;
DiscoverAPI discoverAPI = restAdapter.create(DiscoverAPI.class);
return discoverAPI.getRxPeopleSearchResult(min, max, s, "user");
}
})
.observeOn(AndroidSchedulers.mainThread())
.subscribe(getRxSearchObserver());
}
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我想要的是,当我搜索某些内容时,查询应仅针对当前选中的选项卡进入后端,而不是两个选项卡.我怎样才能做到这一点?
我认为有两种选择。
使用过滤器:
subscription = RxTextView.textChangeEvents(inputSearch)
.debounce(400, TimeUnit.MILLISECONDS)
.filter(textViewTextChangeEvent -> getUserVisibleHint())
.map(..)
...
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或者在调用 setUserVisibleHint 时订阅/取消订阅(如 @Amir 评论):
@Override
public void onResumeFragment() {
//don't subscribe here
}
@Override
public void setUserVisibleHint(boolean isVisibleToUser) {
super.setUserVisibleHint(isVisibleToUser);
if (subscription != null) {
subscription.unsubscribe();
subscription = null;
}
if (isVisibleToUser) {
doSearch();
}
}
@Override
public void onDestroyView() {
super.onDestroyView();
if (subscription != null) {
subscription.unsubscribe();
subscription = null;
}
}
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