将iso日期转换为mongo查询中的时间戳

nir*_*air 6 date mongodb mongodb-query aggregation-framework

这是查询

[
    { 
        "$project": {
            "formattedDate": { 
                "$dateToString": { "format": "%Y-%m-%d", "date": "$ceatedAt" } 
            },
            "createdAtMonth": { "$month": "$ceatedAt" },
            "rating": 1
        }
    },
    {
         "$group": {
             "_id": "$formattedDate",
             "average": { "$avg": "$rating" },
             "month": { "$first": "$createdAtMonth" },
         }
    }
]
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我需要时间戳中的日期.怎么做?

tar*_*pka 11

使用算术集成算你的日期作为被减数,并作为减数.$subtract new Date("1970-01-01")

db.collection.aggregate(
  {
    $project: { "timestamp": { $subtract: [ "$createdAt", new Date("1970-01-01") ] } } 
  }
);
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对于文件

{ "_id": 1, "createdAt": ISODate("2016-09-01T14:35:14.952Z") }
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结果是

{ "_id": 1, "timestamp": NumberLong("1472740514952") }
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如果要按时间戳和(年,月,日)对两者进行分组,则可以将时间戳除以一天中的毫秒数,以使其在每一天(而不是每毫秒)都是唯一的

db.collection.aggregate(
  {
    $project: 
      {
        "timestampByDay":
          {
            $floor: 
              {
                $divide: 
                  [ 
                    { $subtract: [ "$createdAt", new Date("1970-01-01") ] }, 
                    24 * 60 * 60 * 1000 
                  ] 
              }
          },
        "date": "$createdAt"
      }
  },
  {
    $group:
      {
        "_id": "$timestampByDay",
        "date": { $first: "$date" }
      }
  }
);
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Ash*_*shh 10

Mongodb 4.0引入了$toLong将日期转换为时间戳的聚合

db.collection.aggregate([
  { "$project": {
    "createdAt": {
      "$toLong": "$createdAt"
    }
  }}
])
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你可以在这里试试