javascript检查元素是否包含数组的某些部分

Question

我有这样的数组

var ALLOW_SUBNET = ['192.168.1.', '192.168.2.', '192.168.3.' , '192.168.4.'];

我可以使用自己的函数获取PC Client的IP地址:

getIPClient()
    var ipclient = input.getIPClient();

我的问题是如何检查客户端IP是否在我允许的子网内,我尝试使用indexOf()函数,但结果是错误的.例如:

if IP Client is 192.168.1.115 => allow

if IP Client is 192.168.5.115 => deny.

Answer 1

你可以使用Array#some它并检查一部分ALLOW_SUBNET是否ip在位置内0.

function check(ip) {
    return ALLOW_SUBNET.some(function (a) { return !ip.indexOf(a); });
}

var ALLOW_SUBNET = ['192.168.1.', '192.168.2.', '192.168.3.', '192.168.4.'];

console.log(check('192.168.1.115'));
console.log(check('192.168.5.115'));

ES6用 String#startsWith

function check(ip) {
    return ALLOW_SUBNET.some(a => ip.startsWith(a));
}

var ALLOW_SUBNET = ['192.168.1.', '192.168.2.', '192.168.3.', '192.168.4.'];

console.log(check('192.168.1.115'));
console.log(check('192.168.5.115'));

Answer 2

这是一个解决方案.

var ALLOW_SUBNET = ['192.168.1.', '192.168.2.', '192.168.3.', '192.168.4.'];

function checkIP(ip) {
  var allow = false;
  for (var i = 0; i <= ALLOW_SUBNET.length; i++) {
    if (ip.indexOf(ALLOW_SUBNET[i]) > -1) {
      allow = true;
      break;
    }
  }
  return allow;
}

console.log(checkIP('192.168.9.3'));

console.log(checkIP('192.168.1.3'));