穷人的SQL Pivot.在一行中将问题列为每个用户的列和答案

Question

当前查询:

SELECT order_id AS OrderNumber, ordName, ordLastName, question, answer 
FROM cart_survey 
JOIN orders 
    ON cart_survey.order_id=orders.ordID 
JOIN survey_answers 
    ON survey_answers.id=cart_survey.answer_id 
JOIN survey_questions 
    ON survey_questions.id=cart_survey.question_id

结果:

OrderNumber ordName ordLastName question                        answer
8591        Larry   Marshburn   Type of Surgery:                Colostomy  
8591        Larry   Marshburn   Month of Surgery:               2
8591        Larry   Marshburn   Year of surgery:                2010
8591        Larry   Marshburn   Current Ostomy System Brand:    ConvaTec  
8591        Larry   Marshburn   Degree of Satisfaction:         Somewhat Satisfied  
8593        Melvin  Belcher     Type of Surgery:                Urostomy
8593        Melvin  Belcher     Month of Surgery:               9
8593        Melvin  Belcher     Year of surgery:                2010
8593        Melvin  Belcher     Current Ostomy System Brand:    ConvaTec  
8593        Melvin  Belcher     Degree of Satisfaction:         Very Satisfied  

如何正确查询表以提取看起来像这样的结果？单行上的姓名和姓氏以及每列的列和答案的问题.

期望的结果

OrderNumber ordName ordLastName "Type of Surgery" "Month of Surgery" "Year of Surgery" etc.
8591        Larry   Marshbourn   Colostomy         2                  2010
8593        Melvin  Belcher      Urostomy          9                  2010

Answer 1

发布的答案有效但笨拙且缓慢.你可以做我称之为并行聚合的事情:

SELECT
     ID,
     SUM(case when question_id = 1 then 1 else 0 end) as sum1,
     SUM(case when question_id = 2 then 1 else 0 end) as sum2,
     SUM(case when question_id = 3 then 1 else 0 end) as sum3
GROUP BY ID

这将通过表而不是三个,并且非常短.它不是一个完整的演练,但您可以根据您的需求调整概念.