在shell脚本中解析json数组

Question

我需要从json字符串打印键和值.我已经解析了一个简单的json字符串

            {
              "Name": "test1",
              "CreateDate": "2016-08-30T10:52:52Z",
              "Id": "testId1",
            }

我的代码是这样的

 q1=$(echo $x | grep -Po '"Name":.*?[^\\]",'| perl -pe 's/"Name": //; s/^"//; s/",$//');

 q2=$(echo $x | grep -Po '"Id":.*?[^\\]",'| perl -pe 's/"Id": //; s/^"//; s/",$//');

    echo $q1 "," $q2;

但是这段代码不适用于像这样的json字符串

x='{    "TestNames":
        [{
        "Name": "test1",
        "CreateDate": "2016-08-30T10:52:52Z",
        "Id": "testId1"
         }, 
         {
        "Name":  "test2",
        "CreateDate": "2016-08-30T10:52:13Z",
        "Id": "testId2"
    }]
}';

我需要像这样打印

test1 , testId1
test2 , testId2

是否可以使用grep命令获取这样的数据？

Answer 1

首先,你的数据是无效的json,有一个逗号太多了:

{
  "TestNames": [
    {
      "Name": "test1",
      "CreateDate": "2016-08-30T10:52:52Z",
      "Id": "testId1", <--- Remove that!
    },
    {
      "Name": "test2",
      "CreateDate": "2016-08-30T10:52:13Z",
      "Id": "testId2"
    }
  ]
}

一旦你修复了它,你可以用它jq来解析命令行上的json:

echo "$x" | jq -r '.TestNames[]|"\(.Name) , \(.Id)"'

如果你需要保持输出值.

declare -A map1

while read name id ; do
    echo "$name"
    echo "$id"
    map1[$name]=$id

done < <(echo "$x" | jq -r '.TestNames[]|"\(.Name) \(.Id)"')

echo "count : ${#map1[@]}"
echo "in loop: ${map1[$name]}"