Symfony 3:提交表单后设置值

Mr.*_* B. 4 php symfony-forms symfony

我有一个form collection并想field2在提交表单后设置,具体取决于field1. field2在表单中不可编辑,但需要。

我尝试了每个FormEvent (FormEvents::)但收到错误:

SQLSTATE[23000]:违反完整性约束:1048 列“field2”不能为空

// AppBundle/Form/MyFormType.php

// ...
$builder->addEventListener(FormEvents::POST_SUBMIT, function(FormEvent $even) {
    $data = $event->getData();
    $form = $event->getForm();

    if (isset($data['field1'])) { // isset
        $field2 = $this->container->get('repository')->find($data['field1'])->getValue(); // service works

        $data['field2'] = $field2; // !!! doesn't work !!!              
        $data->setField2($field2); // !!! doesn't work !!!    
    }
});
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我究竟做错了什么?提前致谢!

Den*_*mov 5

试试这个

use Symfony\Component\Form\FormEvents;

$builder->addEventListener(FormEvents::PRE_SUBMIT, function(FormEvent $event) {
    $data = $event->getData();
    $form = $event->getForm();

    if (isset($data['field1'])) {
        $field2 = $this->container->get('repository')->find($data['field1'])->getValue();

        $data['field2'] = $field2;              
        $event->setData($data); 
    }
});
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