Angular 2跨组件共享websocket服务

Question

我正在使用angular 2构建一个Web应用程序,其中我希望有多个组件监听同一个服务.此服务返回一个observable,它返回来自websocket的传入数据.我根据这个例子编写了代码.

当前的问题是: 数据从主组件通过服务发送到服务器(使用websockets)并返回数据.但是,只有home.component中的观察者被调用(具有id:room.created和data),而不是导航栏中的观察者.

有人能告诉我为什么两个都不叫？我也尝试将消息$ .subscribe添加到app.component但无济于事.

现在,让我们来看看代码.

返回可观察的消息服务.组件使用此服务发送和接收消息.

@Injectable()
export class MessageService {
    private _messages: Rx.Subject<Message>;
    messages$: Rx.Observable<Message>;

    constructor(wsService: SocketService, private configuration: Configuration) {
      console.log('messag eservice');
      this._messages = <Rx.Subject<Message>>wsService
        .connect()
        .map((response: MessageEvent): Message => {
            let data = JSON.parse(response.data);
            return {
                id: data.id,
                data: data.data,
            }
        });

      this.messages$ = this._messages.asObservable();
    }

    public send(message: Message): void {
      this._messages.next(message);
    }
} 

一种套接字服务,它创建一个websocket连接并将自身绑定到此套接字的输入和输出.

import { Injectable } from '@angular/core';
import * as Rx from "rxjs/Rx";
import { Configuration } from '../app.constants';

@Injectable()
export class SocketService {
    private subject: Rx.Subject<MessageEvent>;

    constructor(private configuration: Configuration){};

    public connect(wsNamespace = ''): Rx.Subject<MessageEvent> {
        var url = this.configuration.wsUrl + wsNamespace;
        if(!this.subject) {
            this.subject = this.create(url);
        }
        return this.subject;
    }

    private create(url): Rx.Subject<MessageEvent> {
        let ws = new WebSocket(url);

        // bind ws events to observable (streams)
        let observable = Rx.Observable.create((obs: Rx.Observer<MessageEvent>) => {
            ws.onmessage = obs.next.bind(obs);
            ws.onerror = obs.error.bind(obs);
            ws.onclose = obs.complete.bind(obs);

            return ws.close.bind(ws);
        });

        // on obs next (send something in the stream) send it using ws.
        let observer = {
            next: (data: Object) => {
                if (ws.readyState === WebSocket.OPEN) {
                    ws.send(JSON.stringify(data));
                }
            },
        };

        return Rx.Subject.create(observer, observable);
    }
}

具有以下提供者的app组件:

  providers: [MessageService, SocketService, Configuration, AuthService]

我在我的主app.component中实例化提供程序,以确保消息和套接字服务没有实例化两次.

我的home.component看起来像这样(这是一个使用路由加载的页面):

import { Component, OnInit } from '@angular/core';
import { Subject } from 'rxjs';
import { Router }    from '@angular/router';
import { MessageService } from '../../services/message.service';

@Component({
  ...
  providers: []
})
export class HomeComponent implements OnInit {
  constructor(private router: Router, private messageService: MessageService) {}

  ngOnInit(): void {
    this.messageService.send({
      id: 'room.create',
      data: {'name': 'Blaat'}
    });

    this.messageService.messages$.subscribe(msg => {
      console.log(msg);
        if(msg.id == 'room.created') {
            // navigate naar games!
        }
    });
  }

}

我的navbar组件看起来像这样(指令):

import { Component, OnInit } from '@angular/core';
import { MessageService } from '../../services/message.service';

@Component({
  moduleId: module.id,
  selector: 'navbar',
  templateUrl: 'navbar.component.html',
  styleUrls: ['navbar.component.css']
})
export class Navbar implements OnInit {

  constructor(private messageService: MessageService) { }

  ngOnInit() {

    this.messageService.messages$.subscribe(msg => {
      console.log(msg);
        if(msg.id == 'room.created') {
            // navigate naar games!
        }
    });
  }

}

Answer 1

看来你的可观察创建函数被多次调用,最可能是两个组件=>两个subscriptions =>两个可观察的创建函数调用.所以最新的observable create fn会覆盖以前的可观察回调到websocket onmessage,onerror和onclose.您应该多播底层的observable以防止这种情况(共享运算符应该这样做).

        // bind ws events to observable (streams)
        let observable = Rx.Observable.create((obs: Rx.Observer<MessageEvent>) => {
            ws.onmessage = obs.next.bind(obs);
            ws.onerror = obs.error.bind(obs);
            ws.onclose = obs.complete.bind(obs);

            return ws.close.bind(ws);
        }).share();

如何正确执行此操作的更有用的资源 https://github.com/ReactiveX/rxjs/blob/master/src/observable/dom/WebSocketSubject.ts https://github.com/blesh/RxSocketSubject