将PySpark与Jupyter Notebook集成

Question

我正在关注这个网站来安装Jupyter Notebook,PySpark并集成两者.

当我需要创建"Jupyter配置文件"时,我读到"Jupyter配置文件"不再存在.所以我继续执行以下几行.

$ mkdir -p ~/.ipython/kernels/pyspark

$ touch ~/.ipython/kernels/pyspark/kernel.json

我打开kernel.json并写下面的内容:

{
 "display_name": "pySpark",
 "language": "python",
 "argv": [
  "/usr/bin/python",
  "-m",
  "IPython.kernel",
  "-f",
  "{connection_file}"
 ],
 "env": {
  "SPARK_HOME": "/usr/local/Cellar/spark-2.0.0-bin-hadoop2.7",
  "PYTHONPATH": "/usr/local/Cellar/spark-2.0.0-bin-hadoop2.7/python:/usr/local/Cellar/spark-2.0.0-bin-hadoop2.7/python/lib/py4j-0.10.1-src.zip",
  "PYTHONSTARTUP": "/usr/local/Cellar/spark-2.0.0-bin-hadoop2.7/python/pyspark/shell.py",
  "PYSPARK_SUBMIT_ARGS": "pyspark-shell"
 }
}

Spark的路径是正确的.

但是,当我运行时,jupyter console --kernel pyspark我得到这个输出:

MacBook:~ Agus$ jupyter console --kernel pyspark
/usr/bin/python: No module named IPython
Traceback (most recent call last):
  File "/usr/local/bin/jupyter-console", line 11, in <module>
    sys.exit(main())
  File "/usr/local/lib/python2.7/site-packages/jupyter_core/application.py", line 267, in launch_instance
    return super(JupyterApp, cls).launch_instance(argv=argv, **kwargs)
  File "/usr/local/lib/python2.7/site-packages/traitlets/config/application.py", line 595, in launch_instance
    app.initialize(argv)
  File "<decorator-gen-113>", line 2, in initialize
  File "/usr/local/lib/python2.7/site-packages/traitlets/config/application.py", line 74, in catch_config_error
    return method(app, *args, **kwargs)
  File "/usr/local/lib/python2.7/site-packages/jupyter_console/app.py", line 137, in initialize
    self.init_shell()
  File "/usr/local/lib/python2.7/site-packages/jupyter_console/app.py", line 110, in init_shell
    client=self.kernel_client,
  File "/usr/local/lib/python2.7/site-packages/traitlets/config/configurable.py", line 412, in instance
    inst = cls(*args, **kwargs)
  File "/usr/local/lib/python2.7/site-packages/jupyter_console/ptshell.py", line 251, in __init__
    self.init_kernel_info()
  File "/usr/local/lib/python2.7/site-packages/jupyter_console/ptshell.py", line 305, in init_kernel_info
    raise RuntimeError("Kernel didn't respond to kernel_info_request")
RuntimeError: Kernel didn't respond to kernel_info_request

Answer 1

将pyspark与jupyter笔记本集成的许多方法.
1. 安装Apache Toree.

  pip install jupyter
  pip install toree
  jupyter toree install --spark_home=path/to/your/spark_directory --interpreters=PySpark

你可以通过检查安装

 jupyter kernelspec list

你将获得toree pyspark内核的条目

  apache_toree_pyspark    /home/pauli/.local/share/jupyter/kernels/apache_toree_pyspark

之后如果需要,可以安装其他解压缩程序,如SparkR,Scala,SQL

 jupyter toree install --interpreters=Scala,SparkR,SQL

2. 将这些行添加到bashrc

  export SPARK_HOME=/path to /spark-2.2.0
  export PATH="$PATH:$SPARK_HOME/bin"    
  export PYSPARK_DRIVER_PYTHON=jupyter
  export PYSPARK_DRIVER_PYTHON_OPTS="notebook"

键入pyspark终端,它将打开一个初始化sparkcontext的jupyter笔记本.

3. pyspark仅作为python包安装
   pip install pyspark

   现在你可以像另一个python包一样导入pyspark.

Answer 2

最简单的方法是使用 findspark。首先创建一个环境变量：

export SPARK_HOME="{full path to Spark}"

然后安装 findspark：

pip install findspark

然后启动 jupyter notebook，以下内容应该可以工作：

import findspark
findspark.init()

import pyspark