Muk*_*ani 2 asp.net-mvc partial-views asp.net-mvc-partialview asp.net-core-mvc
我的观点分为部分观点.因此,在提交时我的模型没有正确重建.
页面视图显示员工数据,其中Employee.Contactinfo是_contactInfo局部视图的模型,其中还具有部分视图_phoneInfo以呈现具有模型Employee.ContactInfo.PhoneInfo的电话信息.
现在的问题是属性的名称.渲染时的Employee.ContactInfo.PhoneInfo.Contact1名称为"Contact1",因此在提交时模型未正确创建,我获得了Employee的原始数据,但是像ContactInfo这样的复杂类型为null.
我认为解决方案是在渲染局部视图时添加前缀.如何在MVC 6中执行以下操作?
employee.cshtml
@model Employee
<% Html.RenderPartial("_conctactInfo", Model.ContactInfo, new ViewDataDictionary
{
TemplateInfo = new System.Web.Mvc.TemplateInfo { HtmlFieldPrefix = "ContactInfo" }
})
%>
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_contactInfo.cshtml
@model ContactInfo
<% Html.RenderPartial("_phoneInfo", Model.PhoneInfo, new ViewDataDictionary
{
TemplateInfo = new System.Web.Mvc.TemplateInfo { HtmlFieldPrefix = "PhoneInfo" }
})
%>
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_phoneInfo.cshtml
@model PhoneInfo
<input asp-for="@Model.Contact1" />
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Muk*_*ani 13
这是解决方案,
namespace Website1.Extensions
{
public static class HtmlHelper
{
public static IHtmlContent Partial(this IHtmlHelper htmlHelper, string partialViewName, object model, string prefix)
{
var viewData = new ViewDataDictionary(htmlHelper.ViewData);
var htmlPrefix = viewData.TemplateInfo.HtmlFieldPrefix;
viewData.TemplateInfo.HtmlFieldPrefix += !Equals(htmlPrefix, string.Empty) ? $".{prefix}" : prefix;
return htmlHelper.Partial(partialViewName, model, viewData);
}
public static Task<IHtmlContent> PartialAsync(this IHtmlHelper htmlHelper, string partialViewName, object model, string prefix)
{
var viewData = new ViewDataDictionary(htmlHelper.ViewData);
var htmlPrefix = viewData.TemplateInfo.HtmlFieldPrefix;
viewData.TemplateInfo.HtmlFieldPrefix += !Equals(htmlPrefix, string.Empty) ? $".{prefix}" : prefix;
return htmlHelper.PartialAsync(partialViewName, model, viewData);
}
}
}
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employee.cshtml
@using Website1.Extensions;
@model Employee
@Html.Partial("_contactInfo", Model.ContactInfo, nameof(Model.ContactInfo))
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_contactInfo.cshtml
@using Website1.Extensions;
@model ContactInfo
@Html.Partial("_phoneInfo", Model.PhoneInfo, nameof(Model.PhoneInfo))
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_phoneInfo.cshtml
@model PhoneInfo
<input asp-for="@Model.Contact1" />
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如果您只需要一次,这将是 _contactInfo 部分视图的快速解决方案
员工.cshtml
@{
var viewData = new ViewDataDictionary(ViewData);
viewData.TemplateInfo.HtmlFieldPrefix = "ContactInfo";
}
<partial name="_conctactInfo" model="Model.ContactInfo" view-data="@viewData"/>
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