Javascript:第二天,跳过周末

Question

我想用javaScript生成下一个工作日.

这是我现在的代码

var today = new Date();
    today.setDate(today.getDate());
    var tdd = today.getDate();
    var tmm = today.getMonth()+1;
    var tyyyy = today.getYear();

    var date = new Date();

    date.setDate(date.getDate()+3);

问题是,星期五它会返回星期六的日期,而我希望它是星期一

Answer 1

这将选择下一个工作日.

var today = new Date(2016, 7, 26,12,0,0,0,0); // Friday at noon
console.log("today, Monday",today,"day #"+today.getDay());
var next = new Date(today.getTime());
next.setDate(next.getDate()+1); // tomorrow
while (next.getDay() == 6 || next.getDay() == 0) next.setDate(next.getDate() + 1);
console.log("no change    ",next,"day #"+next.getDay());
console.log("-------");
// or without a loop:

function getNextWork(d) {
  d.setDate(d.getDate()+1); // tomorrow
  if (d.getDay()==0) d.setDate(d.getDate()+1);
  else if (d.getDay()==6) d.setDate(d.getDate()+2);
  return d;
}
next = getNextWork(today); // Friday
console.log("today, Friday",today);
console.log("next, Monday ",next);
console.log("-------");
today = new Date(2016, 7, 29,12,0,0,0); // Monday at noone
next = getNextWork(today); // Still Monday at noon
console.log("today, Monday",today);
console.log("no change    ",next);
console.log("-------");

// Implementing Rob's comment

function getNextWork1(d) {
  var day = d.getDay(),add=1;
  if (day===5) add=3;
  else if (day===6) add=2;
  d.setDate(d.getDate()+add);  
  return d;
}
today = new Date(2016, 7, 26,12,0,0,0,0); // Friday at noon
next = getNextWork1(today); // Friday
console.log("today, Friday",today);
console.log("next, Monday ",next);
console.log("-------");
today = new Date(2016, 7, 26,12,0,0,0,0); // Monday at noon
next = getNextWork1(today); // Monday
console.log("today, Monday",today);
console.log("no change    ",next);

Answer 2

您可以一次添加 1 天，直到找到不是周六或周日的一天：

function getNextBusinessDay(date) {
  // Copy date so don't affect original
  date = new Date(+date);
  // Add days until get not Sat or Sun
  do {
    date.setDate(date.getDate() + 1);
  } while (!(date.getDay() % 6))
  return date;
}

// today,    Friday 26 Aug 2016
[new Date(), new Date(2016,7,26)].forEach(function(d) {
  console.log(d.toLocaleString() + ' : ' + getNextBusinessDay(d).toLocaleString());
});

您还可以测试这一天并添加额外的时间来度过周末：

// Classic Mon to Fri
function getNextWorkDay(date) {
  let d = new Date(+date);
  let day = d.getDay() || 7;
  d.setDate(d.getDate() + (day > 4? 8 - day : 1));
  return d;
}

for (let i=0, d=new Date(); i<7; i++) {
  console.log(`${d.toDateString()} -> ${getNextWorkDay(d).toDateString()}`);
  d.setDate(d.getDate() + 1);
}

这是另一种方法，可以使用 ECMAScript 工作日数字（Sun = 0、Mon = 1 等）指定工作周。超出范围的日期将移至下一个工作周的开始时间。

当一周不是典型的周一到周五时，这很有用，例如在中东，周六到周三很常见，或者对于一些可能在周五到周一工作的人（或其他）。

function getNext(start, end, date) {
  let d = new Date(+date);
  d.setDate(d.getDate() + 1);
  let day = d.getDay();

  // Adjust end and day if necessary
  // The order of tests and adjustment is important
  if (end < start) {
    if (day <= end) {
      day += 7;
    }
    end += 7;
  }

  // If day is before start, shift to start
  if (day < start) {
    d.setDate(d.getDate() + start - day);

    // If day is after end, shift to next start (treat Sunday as 7)
  } else if (day > end) {
    d.setDate(d.getDate() + 8 - (day || 7));
  }
  return d;
}

// Examples
let f = new Intl.DateTimeFormat('en-GB', {
  weekday:'short',day:'2-digit', month:'short'});
let d = new Date();

[{c:'Work days Mon to Fri',s:1,e:5},
 {c:'Work days Sat to Wed',s:6,e:3},
 {c:'Work days Fri to Mon',s:5,e:1}
].forEach(({c,s,e}) => {
  for (let i = 0; i < 7; i++) {
    !i? console.log(`\n${c}`) : null;
    console.log(`${f.format(d)} => ${f.format(getNext(s, e, d))}`);
    d.setDate(d.getDate() + 1);
  }
});