urg*_*geo 3 python arrays cluster-computing python-itertools
我有一个像这样的数组:
A = [1,3,8,9,3,7,2,1,3,9,6,8,3,8,8,1,2]
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而且我想计算那些"入口集群"的数量>5.在这种情况下,结果应该是4,因为:
[1, 3, (8,9), 3, (7), 2, 1, 3, (9,6,8), 3, (8,8), 1, 2]
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给定L数组的长度,我可以这样做:
A = [1,3,8,9,3,7,2,1,3,9,6,8,3,8,8,1,2]
A = np.array(A)
for k in range(0,L):
if A[k]>5:
print k, A[k]
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这给了我所有大于的条目5.但是我怎么能对每一组数字进行分组呢?
你可以使用groupby来自的功能itertools.
from itertools import groupby
A = [1,3,8,9,3,7,2,1,3,9,6,8,3,8,8,1,2]
result = [tuple(g) for k, g in groupby(A, lambda x: x > 5) if k]
print(result)
# [(8, 9), (7,), (9, 6, 8), (8, 8)]
print(len(result))
# 4
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