HTML在Rails 3中转义

Question

我在这个视图中有一个方法调用

<%= Navigation.with(params) do |menu| 
              if current_user && current_user.can_verify?
                menu.item("Listings", manage_listings_path())
                menu.item("Listing changes", needing_change_approval_manage_listings_path())
                menu.item("Flagged Items", flagged_manage_listings_path())
                menu.item("Transfers", manage_listing_transfers_path())
                menu.item("Reviews", manage_listing_reviews_path())
              end
              if current_user && current_user.admin?
                menu.item("Log", manage_verifications_path())
                menu.item("Indexer Compensations", manage_compensations_path())
                menu.item("Users", manage_users_path())
              end
            end%>

拆分下面的字符串

"<li><a href="/manage/listings" class="active">Listings</a></li> <li><a href="/manage/listings/needing_change_approval">Listing changes</a></li> <li><a href="/manage/listings/flagged">Flagged Items</a></li> <li><a href="/manage/listing_transfers">Transfers</a></li> <li><a href="/manage/listing_reviews">Reviews</a></li> <li><a href="/manage/verifications">Log</a></li> <li><a href="/manage/compensations">Indexer Compensations</a></li> <li><a href="/manage/users">Users</a></li>"

我只是在我的页面中得到这个字符串.我希望它们是由CSS完美设计的菜单.我只是在我的页面中获取上述原始文本.如何将此字符串转换为浏览器将其视为HTML.

请帮忙

这是导航类

class NavigationMenu < ActionView::Base
  def initialize(params)
    @params = params
  end

  def item(title, path, options={})
    @items ||= Array.new
    unless (route = Rails.application.routes.recognize_path(path,:method => options[:method]|| :get))
      raise "Unrecognised path #{path}, are you sure it's in routes.rb?"
    end

    @items << content_tag(:li, link_to(title,path, :class => (@params[:controller] == route[:controller] && @params[:action] == route[:action])? 'active' : nil))

  end

  def output
    return '' if @items.blank?
    content_tag(:ul, @items.join("\n"), :id => 'navigation')
  end
end

class Navigation
  def self.with(params, &block)
    menu = NavigationMenu.new(params)
    yield menu
    menu.output
  end
end

Answer 1

您必须添加对raw方法的调用:

<%= raw ... %>

这是必要的,因为在Rails 3中,默认情况下每个字符串都会被转义,除非您使用该raw方法.它类似于hRails 2中方法的反转,默认情况下每个字符串都是非转义的,除非您使用该h方法.

例:

Rails 2中的代码...

<%= h "String which must be escaped" %>
<%= "String which must be output raw %>

...必须在Rails 3中这样:

<%= "String which must be escaped" %>
<%= raw "String which must be output raw %>

(虽然额外的调用h不会对Rails 3造成任何伤害)