Angular2 - 多个依赖的顺序http api调用

Ant*_*Day 8 api service http observable angular

我正在构建一个Angular2应用程序,其中一个组件需要进行多个API调用,这些调用依赖于之前的API调用.

我目前有一个服务,它进行API调用以获取电视节目列表.对于每个节目,我需要多次调用不同的API来逐步完成结构,以确定节目是否存在于Plex服务器上.

API文档在这里

对于每个节目,我需要进行以下调用并获取正确的数据以确定它是否存在:(假设我们有变量<TVShow>, <Season>, <Episode>)

http://baseURL/library/sections/?X-Plex-Token=xyz 会告诉我: title="TV Shows" key="2"

http://baseURL/library/sections/2/all?X-Plex-Token=xyz&title=<TVShow> 会告诉我: key="/library/metadata/2622/children"

http://baseURL/library/metadata/2622/children?X-Plex-Token=xyz 会告诉我: index="<Season>" key="/library/metadata/14365/children"

http://baseURL/library/metadata/14365/children?X-Plex-Token=xyz会告诉我:index="<Episode>"这意味着我的插曲存在.

响应是在json中,我删除了很多多余的文本.在每个阶段,我需要检查正确的字段是否存在(<TVShow>, <Season>, <Episode>),以便它们可以用于下一次调用.如果没有,我需要返回该节目不存在.如果是的话,我可能想要为节目返回一个id.


我看了很多例子,包括promise,async和flatmap,但我不知道如何根据我见过的其他例子解决这个问题.


这是我获取节目列表的方法.(shows.service.ts)

export class ShowsHttpService {
    getShows(): Observable<Show[]> {
        let shows$ = this._http
            .get(this._showHistoryUrl)
            .map(mapShows)
            .catch(this.handleError);
        return shows$;
    }
}

function mapShows(response:Response): Show[] {
    return response.json().data.map(toShow);
}

function toShow(r:any): Show {
    let show = <Show>({
        episode: r.episode,
        show_name: r.show_name,
        season: r.season,
        available : false,    // I need to fill in this variable if the show is available when querying the Plex API mentioned above.
    });
    // My best guess is here would be the right spot to call the Plex API as we are dealing with a single show at a time at this point, but I cannot see how.
    return show;
}
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以下是组件中的相关代码(shows.component.ts)

public getShows():any {
    this._ShowsHttpService
        .getShows()
        .subscribe(w => this.shows = w);
    console.log(this.shows);
}
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奖励积分

以下是明显的下一个有趣但不必要的问题:

  1. 第一个API查询比等待所有其他查询要快得多(4个查询*~10个节目).可以返回初始列表,然后available在准备好时更新状态.
  2. 第一个Plex调用key="2"只需要执行一次.它可以是硬编码的,但相反,它可以执行一次并记住吗?
  3. 有没有办法减少API调用的数量?我可以看到我可以删除show过滤器,并在客户端上搜索结果,但这也不是理想的.
  4. 每个节目的4个调用必须按顺序进行,但每个节目可以并行查询以提高速度.这可以实现吗?

任何想法将不胜感激!

Joh*_*ird 3

不确定我是否完全理解你的问题,但这就是我所做的:

我进行第一个 http 调用,然后当订阅触发时,它调用completeLogin。然后我可以用它自己的完整功能触发另一个 http 调用并重复该链。

这是组件代码。用户已填写登录信息并按下登录:

onSubmit() {
   console.log(' in on submit');
   this.localUser.email = this.loginForm.controls["email"].value;
   this.localUser.password = this.loginForm.controls["password"].value;
   this.loginMessage = "";
   this.checkUserValidation();
}

checkUserValidation() { 
   this.loginService.getLoggedIn()
      .subscribe(loggedIn => {
         console.log("in logged in user validation")
         if(loggedIn.error != null || loggedIn.error != undefined || loggedIn.error != "") {
            this.loginMessage = loggedIn.error;
         }
      });

      this.loginService.validateUser(this.localUser);
}
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这会调用loginservice ValidateUser方法

validateUser(localUser: LocalUser) {
   this.errorMessage = "";
   this.email.email = localUser.email;
   var parm = "validate~~~" + localUser.email + "/"
   var creds = JSON.stringify(this.email);
   var headers = new Headers();
   headers.append("content-type", this.constants.jsonContentType);

   console.log("making call to validate");
   this.http.post(this.constants.taskLocalUrl + parm, { headers: headers })
      .map((response: Response) => {
         console.log("json = " + response.json());
         var res = response.json();
         var result = <AdminResponseObject>response.json();
         console.log(" result: " + result);
         return result;
      })
      .subscribe(
         aro => {
            this.aro = aro
         },
         error => {
            console.log("in error");
            var errorObject = JSON.parse(error._body);
            this.errorMessage = errorObject.error_description;
            console.log(this.errorMessage);
         },
         () => this.completeValidateUser(localUser));
            console.log("done with post");
     }

completeValidateUser(localUser: LocalUser) {
   if (this.aro != undefined) {
      if (this.aro.errorMessage != null && this.aro.errorMessage != "") {
         console.log("aro err " + this.aro.errorMessage);
         this.setLoggedIn({ email: localUser.email, password: localUser.password, error: this.aro.errorMessage });
      } else {
         console.log("log in user");
         this.loginUser(localUser);
      }
   } else {
      this.router.navigate(['/verify']);
   }
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}

在我的登录服务中,我调用授权服务,该服务返回可观察的令牌。

loginUser(localUser: LocalUser) {
   this.auth.loginUser(localUser)
   .subscribe(
      token => {
         console.log('token = ' + token)
         this.token = token
      },
      error => {
         var errorObject = JSON.parse(error._body);
         this.errorMessage = errorObject.error_description;
         console.log(this.errorMessage);
         this.setLoggedIn({ email: "", password: "", error: this.errorMessage });
      },
      () => this.completeLogin(localUser));
}
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在授权服务中:

loginUser(localUser: LocalUser): Observable<Token> {
   var email = localUser.email;
   var password = localUser.password;

    var headers = new Headers();
    headers.append("content-type", this.constants.formEncodedContentType);

    var creds:string = this.constants.grantString + email + this.constants.passwordString + password;
    return this.http.post(this.constants.tokenLocalUrl, creds, { headers: headers })
         .map(res => res.json())
}
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这段代码的重点是,首先调用登录服务的 validateUser 方法,根据返回信息,根据返回信息,如果有效,我调用登录服务的 loginUser 方法。只要您需要,这条链条就可以继续存在。您可以设置类级别变量来保存链中每个方法中所需的信息,以决定下一步要做什么。

还要注意,您可以在服务中订阅返回并在那里处理它,它不必返回到组件。

好的,这里是:

public getShows():any {
   this._ShowsHttpService
      .getShows()
      .subscribe(
         w => this.shows = w,
         error => this.errorMessage = error,
         () => this.completeGetShows());
}

completeGetShow() {

   //any logic here to deal with previous get;

   this.http.get#2()
      .subscribe(
         w => this.??? = w),
         error => this.error = error,
         () => this.completeGet#2);
}

completeGet#2() {

   //any logic here to deal with previous get;

   this.http.get#3()
      .subscribe(
         w => this.??? = w),
         error => this.error = error,
         () => this.completeGet#3);
}

completeGet#3() {

   //any logic here to deal with previous get;

   //another http: call like above to infinity....
}
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