Hom*_*r_J 2 mysql sql-order-by
我有以下代码:
SELECT q21coding, COUNT(q21coding) AS Count
FROM `tresults_acme`
WHERE q21 IS NOT NULL AND q21 <> ''
GROUP BY q21coding
ORDER BY Count DESC
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它带回了以下内容:
q21coding Count
Difficulty in navigating/finding content 53
Positive comments 28
Suggestions for improvement 14
Inappropriate content/use 13
Improve search facility 6
Include information about staff and teams 5
Content needs updating 4
Other 30
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你会注意到其他是第二个 - 有没有办法确保其他总是在底部而不管计数大小?
谢谢,
荷马