如何将List拆分为段

Question

假设我需要将给定列表拆分为3个段,如下所示:

val l = (0 until 5).toList
val segments = l.tails.map(_.take(3)).filter(_.size == 3).toList
segments: List[List[Int]] = List(List(0, 1, 2), List(1, 2, 3), List(2, 3, 4))

我得到了segments我的需要,但代码显然是丑陋的.你会怎么改写它？

Answer 1

用途sliding:

val segments: Iterator[List[Int]] = l.sliding(3)

segments.toList
> List[List[Int]] = List(List(0, 1, 2), List(1, 2, 3), List(2, 3, 4))