Jil*_*ill 6 junit spring-integration mockito
我想嘲笑外部电话.
ResponseEntity<?> httpResponse = requestGateway.pushNotification(xtifyRequest);Run Code Online (Sandbox Code Playgroud)
requestGateway是一个界面.
public interface RequestGateway
{
ResponseEntity<?> pushNotification(XtifyRequest xtifyRequest);
}
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以下是我正在尝试的测试方法.
@Test
public void test()
{
ResponseEntity<?> r=new ResponseEntity<>(HttpStatus.ACCEPTED);
when(requestGateway.pushNotification(any(XtifyRequest.class))).thenReturn(r);
}
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上面的when语句中存在编译错误,称其为无效类型.甚至thurgg类型为ResponseEntity.
有谁可以帮我解决这个问题?
Nit*_*mas 11
您可以改为使用type-unsafe方法
doReturn(r).when(requestGateway.pushNotification(any(XtifyRequest.class)));
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或者您可以在模拟时删除类型信息
ResponseEntity r=new ResponseEntity(HttpStatus.ACCEPTED);
when(requestGateway.pushNotification(any(XtifyRequest.class))).thenReturn(r);
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