Til*_* S. 0 python python-requests
例如我的代码是:
import requests
r = requests.get('https://www.python.org')
r.status_code
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结果是:
Traceback (most recent call last):
File "C:\Users\Till\workspace\firstproject\Learning_python\Web_crawler.py", line 6, in <module>
import requests
File "C:\Python32\lib\site-packages\requests\__init__.py", line 64, in <module>
from .models import Request, Response, PreparedRequest
File "C:\Python32\lib\site-packages\requests\models.py", line 856
http_error_msg = u'%s Client Error: %s for url: %s' % (self.status_code, reason, self.url)
^
SyntaxError: invalid Syntax
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Mar*_*ers 11
请求需要Python 3.3或更高版本.它在Python 3.2上不起作用,因为该版本不支持u'...'字符串文字所需的兼容性语法.
请求正式支持Python 2.6-2.7和3.3-3.5,并在PyPy上运行良好.
请注意,3.2相当......古老.您真的想要升级到更新的Python 3版本.
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