如何在不使用查询语法的情况下在Entity Framework中执行左外连接?

Ran*_*rez 7 c# linq entity-framework

我正在尝试使用linq的查询语法将此查询转换为基于方法的语法.

这是查询:

  var products = from p in context.Products
                 join t in context.TopSellings
                 on p.Id equals t.Id into g
                 from tps in g.DefaultIfEmpty()
                 orderby tps.Rating descending
                 select new
                 {
                     Name = p.Name,
                     Rating = tps.Rating == null ? 0 : tps.Rating
                 };
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上面的查询产生这个SQL查询:

{SELECT 
    [Project1].[Id] AS [Id], 
    [Project1].[Name] AS [Name], 
    [Project1].[C1] AS [C1]
    FROM ( SELECT 
        [Extent1].[Id] AS [Id], 
        [Extent1].[Name] AS [Name], 
        CASE WHEN ([Extent2].[Rating] IS NULL) THEN 0 ELSE [Extent2].[Rating] END AS [C1], 
        [Extent2].[Rating] AS [Rating]
        FROM  [dbo].[Products] AS [Extent1]
        LEFT OUTER JOIN [dbo].[TopSellings] AS [Extent2] ON [Extent1].[Id] = [Extent2].[Id]
    )  AS [Project1]
    ORDER BY [Project1].[Rating] DESC}
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到目前为止,我尝试过的是这样的:

var products = context.Products
    .Join(inner: context.TopSellings.DefaultIfEmpty(), 
          outerKeySelector: c => c.Id, innerKeySelector: y => y.Id, 
          resultSelector: (j, k) => new { Name = j.Name, Rating = k.Rating == null ? 0 : k.Rating })
    .OrderByDescending(p => p.Rating);
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并且这个产生了一个不同的sql查询(当然,关于如何在程序中使用数据,它具有不同的含义):

{SELECT 
    [Project1].[Id] AS [Id], 
    [Project1].[Name] AS [Name], 
    [Project1].[C1] AS [C1]
    FROM ( SELECT 
        [Extent1].[Id] AS [Id], 
        [Extent1].[Name] AS [Name], 
        CASE WHEN ([Join1].[Rating] IS NULL) THEN 0 ELSE [Join1].[Rating] END AS [C1]
        FROM  [dbo].[Products] AS [Extent1]
        INNER JOIN  (SELECT [Extent2].[Id] AS [Id], [Extent2].[Rating] AS [Rating]
            FROM   ( SELECT 1 AS X ) AS [SingleRowTable1]
            LEFT OUTER JOIN [dbo].[TopSellings] AS [Extent2] ON 1 = 1 ) AS [Join1] ON [Extent1].[Id] = [Join1].[Id]
    )  AS [Project1]
    ORDER BY [Project1].[C1] DESC}
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您的答案将会非常有用,非常感谢!

Jef*_*ado 7

通常,您可以通过访问查询的Expression属性来获取从任何查询表达式中使用的确切表达式.然后只需分析该表达式并重现它.

var expr = products.Expression;
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另一方面,使用查询语法的每个表达式都具有直接的转换.与into子句的部分连接对应于a,GroupJoin()而额外的from子句对应于a SelectMany().这应该产生一个等价的查询:

var products = context.Products.GroupJoin(context.TopSellings,
        p => p.Id, t => t.Id, (p, g) => new { p, g })
    .SelectMany(x => x.g.DefaultIfEmpty(),
        (x, tps) => new { x.p, x.g, tps })
    .OrderByDescending(x => x.tps.Rating)
    .Select(x => new { x.p.Name, Rating = x.tps.Rating == null ? 0 : x.tps.Rating });
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但是你可以删除一些冗余,削减不再使用的变量并利用一些有用的运算符.请注意,它可能会影响生成的实际查询,因此它不完全匹配,但它应该足够接近.

var products = context.Products.GroupJoin(context.TopSellings,
    p => p.Id, t => t.Id,
    (p, g) => g.DefaultIfEmpty()
        .OrderByDescending(tps => tps.Rating)
        .Select(tps => new { p.Name, Rating = tps.Rating ?? 0 })
);
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