如何从 numpy float32 数组创建图像?

Ida*_*n.c 7 python numpy python-imaging-library

我有一个numpy.ndarray数组,其中包含float32. 图像尺寸应为 226×226。我试图用来PIL.Image创建图像,但出现错误。我读了PIL.Image.fromarray需要的对象和方式,以及浮法我要打电话fromarray'F'我试过。

这就是我试图做的:

from PIL import Image
img = Image.fromarray(slice56, mode='F')
#type(slice56) = <type 'numpy.ndarray'>
#slice56 = array([ 0.,  0.,  0., ...,  0.,  0.,  0.], dtype=float32)
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我收到这个错误:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib64/python2.6/site-packages/PIL/Image.py", line 1860, in fromarray
    return frombuffer(mode, size, obj, "raw", mode, 0, 1)
  File "/usr/lib64/python2.6/site-packages/PIL/Image.py", line 1805, in frombuffer
    return apply(fromstring, (mode, size, data, decoder_name, args))
  File "/usr/lib64/python2.6/site-packages/PIL/Image.py", line 1743, in fromstring
    im = new(mode, size)
  File "/usr/lib64/python2.6/site-packages/PIL/Image.py", line 1710, in new
    return Image()._new(core.fill(mode, size, color))
TypeError: argument 2 must be sequence of length 2, not 1
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任何人都可以提出一个想法如何做到这一点?或者如何解决这个错误?

jti*_*usj 6

我同意 DavidG 的回答是从 numpy 数组绘制图像的快速解决方案。但是,如果您有充分的理由坚持使用PIL.Image,那么最接近您已经完成的工作的方法是这样的:

from PIL import Image
import numpy as np

slice56 = np.random.random((226, 226))

# convert values to 0 - 255 int8 format
formatted = (slice56 * 255 / np.max(slice56)).astype('uint8')
img = Image.fromarray(formatted)
img.show()
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然后它会产生如下给定的随机数:

图像