如何在查询XML时在LINQ中添加OR条件？

Question

问题:返回所有记录where Jon Doe =<bus_contact> 或 <bus_sponsor>.

当前代码返回记录1,因此仅使用一个查询返回记录1和2需要进行哪些修改？

XML

<root>
  <row>
    <project_id>1</project_id>
    <project_name>Name1</project_name>
    <bus_contact>Jon Doe</bus_contact>
    <bus_sponsor>Bruce Wayne</bus_sponsor>
  </row>
  <row>
    <project_id>2</project_id>
    <project_name>Name2</project_name>
    <bus_contact>Peter Parker</bus_contact>
    <bus_sponsor>Jon Doe</bus_sponsor>
  </row>
</root>

C#

class Program
{
    static void Main (string[] args)
    {
        XElement main = XElement.Load ("master_list.xml");

        var results = main.Descendants ("row")
            .Descendants ("bus_contact")
            .Where (e => e.Value == "Jon Doe")
            .Select (e => e.Parent)               
            .Select (e => new {
                project_id = e.Descendants ("project_id").FirstOrDefault ().Value,
                project_name = e.Descendants ("project_name").FirstOrDefault ().Value
            });

        foreach (var result in results)
            Console.WriteLine ("{0}, {1}", result.project_id, result.project_name);
        Console.ReadLine ();
    }
}

编辑:这与可能的重复链接中指出的问题不完全相同.是的,它部分地指的是这一点,但作为一个初学者得到一个适当的上下文的答案,接受的答案提供,是非常有帮助的.

Answer 1

用||结合Any，就像这样：

var results = main.Descendants("row")
    .Where(r =>
        r.Descendants("bus_contact").Any(c => c.Value == "Jon Doe")
    ||  r.Descendants("bus_sponsor").Any(c => c.Value == "Jon Doe")
    );

UsingAny允许您按条件查询子级，而无需实际下降到子级。这消除了通过选择爬回树的必要性Parent。