我可以使用用于扁平化XML文件的库或机制吗?
现有:
<A>
<B>
<ConnectionType>a</ConnectionType>
<StartTime>00:00:00</StartTime>
<EndTime>00:00:00</EndTime>
<UseDataDictionary>N</UseDataDictionary>
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期望的:
A.B.ConnectionType = a
A.B.StartTime = 00:00:00
A.B.EndTime = 00:00:00
A.B.UseDataDictionary = N
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通过xmltodict
将XML文件转换为字典,并结合此答案以使a变平dict
,这应该是可能的。
例:
# Original code: https://codereview.stackexchange.com/a/21035
from collections import OrderedDict
def flatten_dict(d):
def items():
for key, value in d.items():
if isinstance(value, dict):
for subkey, subvalue in flatten_dict(value).items():
yield key + "." + subkey, subvalue
else:
yield key, value
return OrderedDict(items())
import xmltodict
# Convert to dict
with open('test.xml', 'rb') as f:
xml_content = xmltodict.parse(f)
# Flatten dict
flattened_xml = flatten_dict(xml_content)
# Print in desired format
for k,v in flattened_xml.items():
print('{} = {}'.format(k,v))
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输出:
A.B.ConnectionType = a
A.B.StartTime = 00:00:00
A.B.EndTime = 00:00:00
A.B.UseDataDictionary = N
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