为什么块按此顺序运行?

kse*_*een 4 .net c# dataflow task-parallel-library tpl-dataflow

这是一个简短的代码示例,可以快速向您介绍我的问题:

using System;
using System.Linq;
using System.Threading.Tasks;
using System.Threading.Tasks.Dataflow;

namespace DataflowTest
{
    class Program
    {
        static void Main(string[] args)
        {
            var firstBlock = new TransformBlock<int, int>(x => x, new ExecutionDataflowBlockOptions
            {
                MaxDegreeOfParallelism = 4
            });
            var secondBlock = new TransformBlock<int,string>(async x =>
            {
                if (x == 12)
                {
                    await Task.Delay(5000);
                    return $"{DateTime.Now}: Message is {x} (This is delayed message!) ";
                }

                return $"{DateTime.Now}: Message is {x}";
            }, new ExecutionDataflowBlockOptions
            {
                MaxDegreeOfParallelism = 4
            });
            var thirdBlock = new ActionBlock<string>(s => Console.WriteLine(s), new ExecutionDataflowBlockOptions
            {
                MaxDegreeOfParallelism = 4
            });

            firstBlock.LinkTo(secondBlock);
            secondBlock.LinkTo(thirdBlock);

            var populateTask = Task.Run(async () =>
            {
                foreach (var x in Enumerable.Range(1, 15))
                {
                    await firstBlock.SendAsync(x);
                }
            });

            populateTask.Wait();
            secondBlock.Completion.Wait();
        }
    }
}
Run Code Online (Sandbox Code Playgroud)

输出是:

09.08.2016 15:03:08: Message is 1
09.08.2016 15:03:08: Message is 5
09.08.2016 15:03:08: Message is 6
09.08.2016 15:03:08: Message is 7
09.08.2016 15:03:08: Message is 8
09.08.2016 15:03:08: Message is 9
09.08.2016 15:03:08: Message is 10
09.08.2016 15:03:08: Message is 11
09.08.2016 15:03:08: Message is 3
09.08.2016 15:03:08: Message is 2
09.08.2016 15:03:08: Message is 4
09.08.2016 15:03:13: Message is 12 (This is delayed message!)
09.08.2016 15:03:08: Message is 15
09.08.2016 15:03:08: Message is 13
09.08.2016 15:03:08: Message is 14
Run Code Online (Sandbox Code Playgroud)

为什么这个订单以及如何更改网络以获得下面的输出?

09.08.2016 15:03:08: Message is 1
09.08.2016 15:03:08: Message is 5
09.08.2016 15:03:08: Message is 6
09.08.2016 15:03:08: Message is 7
09.08.2016 15:03:08: Message is 8
09.08.2016 15:03:08: Message is 9
09.08.2016 15:03:08: Message is 10
09.08.2016 15:03:08: Message is 11
09.08.2016 15:03:08: Message is 3
09.08.2016 15:03:08: Message is 2
09.08.2016 15:03:08: Message is 4
09.08.2016 15:03:08: Message is 15
09.08.2016 15:03:08: Message is 13
09.08.2016 15:03:08: Message is 14
09.08.2016 15:03:13: Message is 12 (This is delayed message!)
Run Code Online (Sandbox Code Playgroud)

所以我想知道为什么所有其他块(或这里的任务)都在等待延迟块?


UPDATE

既然你们让我更详细地解释我的问题,我就把这个样本做得更接近我正在研究的真正的管道.假设应用程序下载一些数据并根据返回的响应计算哈希值.

using System;
using System.Diagnostics;
using System.Linq;
using System.Net.Http;
using System.Security.Cryptography;
using System.Text;
using System.Threading.Tasks;
using System.Threading.Tasks.Dataflow;

namespace DataflowTest
{
    class Program
    {
        static void Main(string[] args)
        {
            var firstBlock = new TransformBlock<int, string>(x => x.ToString(), new ExecutionDataflowBlockOptions { MaxDegreeOfParallelism = 4 });

            var secondBlock = new TransformBlock<string, Tuple<string, string>>(async x =>
            {
                using (var httpClient = new HttpClient())
                {
                    if (x == "4") await Task.Delay(5000);

                    var result = await httpClient.GetStringAsync($"http://scooterlabs.com/echo/{x}");
                    return new Tuple<string, string>(x, result);
                }
            }, new ExecutionDataflowBlockOptions { MaxDegreeOfParallelism = 4 });

            var thirdBlock = new TransformBlock<Tuple<string, string>, Tuple<string, byte[]>>(x =>
             {
                 using (var algorithm = SHA256.Create())
                 {
                     var bytes = Encoding.UTF8.GetBytes(x.Item2);
                     var hash = algorithm.ComputeHash(bytes);

                     return new Tuple<string, byte[]>(x.Item1, hash);
                 }
             }, new ExecutionDataflowBlockOptions { MaxDegreeOfParallelism = 4 });

            var fourthBlock = new ActionBlock<Tuple<string, byte[]>>(x =>
            {
                var output = $"{DateTime.Now}: Hash for element #{x.Item1}: {GetHashAsString(x.Item2)}";

                Console.WriteLine(output);
            }, new ExecutionDataflowBlockOptions { MaxDegreeOfParallelism = 4 });

            firstBlock.LinkTo(secondBlock);
            secondBlock.LinkTo(thirdBlock);
            thirdBlock.LinkTo(fourthBlock);

            var populateTasks = Enumerable.Range(1, 10).Select(x => firstBlock.SendAsync(x));
            Task.WhenAll(populateTasks).ContinueWith(x => firstBlock.Complete()).Wait();

            fourthBlock.Completion.Wait();
        }

        private static string GetHashAsString(byte[] bytes)
        {
            var sb = new StringBuilder();
            int i;
            for (i = 0; i < bytes.Length; i++)
            {
                sb.AppendFormat("{0:X2}", bytes[i]);
                if (i % 4 == 3) sb.Append(" ");
            }

            return sb.ToString();
        }
    }
}
Run Code Online (Sandbox Code Playgroud)

我们来看看请求的顺序:

要求

这绝对有道理.所有请求都是尽快提出的.缓慢的第四个请求在列表的末尾.

现在让我们看看我们有什么输出:

09.08.2016 20:44:53: Hash for element #3: 4D0AB933 EE521204 CA784F3E 248EC698 F9E4D5F3 8F23A78F 3A00E069 29E73E32
09.08.2016 20:44:53: Hash for element #2: 4D0AB933 EE521204 CA784F3E 248EC698 F9E4D5F3 8F23A78F 3A00E069 29E73E32
09.08.2016 20:44:53: Hash for element #1: 4D0AB933 EE521204 CA784F3E 248EC698 F9E4D5F3 8F23A78F 3A00E069 29E73E32
09.08.2016 20:44:58: Hash for element #6: FC86E4F8 A83036BA 365BC7EE F9371778 59A11186 ED12A43C 3885D686 5004E6B3
09.08.2016 20:44:58: Hash for element #8: FC86E4F8 A83036BA 365BC7EE F9371778 59A11186 ED12A43C 3885D686 5004E6B3
09.08.2016 20:44:58: Hash for element #9: FC86E4F8 A83036BA 365BC7EE F9371778 59A11186 ED12A43C 3885D686 5004E6B3
09.08.2016 20:44:58: Hash for element #10: FC86E4F8 A83036BA 365BC7EE F9371778 59A11186 ED12A43C 3885D686 5004E6B3
09.08.2016 20:44:58: Hash for element #4: 44A63CBF 8E27D0DD AFE5A761 AADA4E49 AA52FE8E E3D7DC82 AFEAAF1D 72A9BC7F
09.08.2016 20:44:58: Hash for element #5: FC86E4F8 A83036BA 365BC7EE F9371778 59A11186 ED12A43C 3885D686 5004E6B3
09.08.2016 20:44:58: Hash for element #7: FC86E4F8 A83036BA 365BC7EE F9371778 59A11186 ED12A43C 3885D686 5004E6B3
Run Code Online (Sandbox Code Playgroud)

您可以看到第三个响应结束后立即计算出第三个之后的所有哈希值.

因此,基于这两个事实,我们可以说所有下载的页面都在等待缓慢的第四个请求完成.最好不要在下载数据后立即等待第四个请求和计算哈希值.有什么办法可以实现吗?

kse*_*een 5

好的,通过@SirRufo的引用,我开始考虑实现我自己的TransformBlock,以满足我的需求并处理传入的项目而不考虑订购.这样一来,它不会破坏网络,在部分下载中建立块之间的差距,并且将是优雅的方式.

所以我开始研究我该怎么做以及如何做到这一点.查看TransformBlock自己的来源似乎是一个很好的起点,所以我TransformBlockGithub开源并开始分析它.

从课程开始,我发现了这个有趣的事情://如果采用并行性,我们将需要支持无序完成的重新排序消息.

// However, a developer can override this with EnsureOrdered == false.
if (dataflowBlockOptions.SupportsParallelExecution && dataflowBlockOptions.EnsureOrdered)
{
    _reorderingBuffer = new ReorderingBuffer<TOutput>(this, (owningSource, message) => ((TransformBlock<TInput, TOutput>)owningSource)._source.AddMessage(message));
}
Run Code Online (Sandbox Code Playgroud)

看起来像我们想要的确切的东西!让我们在Github上的课堂上看到这个EnsureOrdered选项:DataflowBlockOptions

/// <summary>Gets or sets whether ordered processing should be enforced on a block's handling of messages.</summary>
/// <remarks>
/// By default, dataflow blocks enforce ordering on the processing of messages. This means that a
/// block like <see cref="TransformBlock{TInput, TOutput}"/> will ensure that messages are output in the same
/// order they were input, even if parallelism is employed by the block and the processing of a message N finishes 
/// after the processing of a subsequent message N+1 (the block will reorder the results to maintain the input
/// ordering prior to making those results available to a consumer).  Some blocks may allow this to be relaxed,
/// however.  Setting <see cref="EnsureOrdered"/> to false tells a block that it may relax this ordering if
/// it's able to do so.  This can be beneficial if the immediacy of a processed result being made available
/// is more important than the input-to-output ordering being maintained.
/// </remarks>
public bool EnsureOrdered
{
    get { return _ensureOrdered; }
    set { _ensureOrdered = value; }
}
Run Code Online (Sandbox Code Playgroud)

它看起来非常好,所以我立即切换到IDE来设置它.不幸的是,没有这样的设置:

没有EnsureOrdered

我一直在寻找并发现这个说明:

4.5.25-β-23019

包已重命名为System.Threading.Tasks.Dataflow

当我用Google搜索并发现这个包时,叫System.Threading.Tasks.Dataflow!所以我卸载了Microsoft.Tpl.Dataflow包并System.Threading.Tasks.Dataflow通过发布安装:

Install-Package System.Threading.Tasks.Dataflow
Run Code Online (Sandbox Code Playgroud)

还有EnsureOrdered选择权.我更新了代码,设置EnsureOrderedfalse:

using System;
using System.Diagnostics;
using System.Linq;
using System.Net.Http;
using System.Security.Cryptography;
using System.Text;
using System.Threading.Tasks;
using System.Threading.Tasks.Dataflow;

namespace DataflowTest
{
    class Program
    {
        static void Main(string[] args)
        {
            var options = new ExecutionDataflowBlockOptions { MaxDegreeOfParallelism = 4, EnsureOrdered = false };
            var firstBlock = new TransformBlock<int, string>(x => x.ToString(), options);

            var secondBlock = new TransformBlock<string, Tuple<string, string>>(async x =>
            {
                using (var httpClient = new HttpClient())
                {
                    if (x == "4") await Task.Delay(5000);

                    var result = await httpClient.GetStringAsync($"http://scooterlabs.com/echo/{x}");
                    return new Tuple<string, string>(x, result);
                }
            }, options);

            var thirdBlock = new TransformBlock<Tuple<string, string>, Tuple<string, byte[]>>(x =>
             {
                 using (var algorithm = SHA256.Create())
                 {
                     var bytes = Encoding.UTF8.GetBytes(x.Item2);
                     var hash = algorithm.ComputeHash(bytes);

                     return new Tuple<string, byte[]>(x.Item1, hash);
                 }
             }, options);

            var fourthBlock = new ActionBlock<Tuple<string, byte[]>>(x =>
            {
                var output = $"{DateTime.Now}: Hash for element #{x.Item1}: {GetHashAsString(x.Item2)}";

                Console.WriteLine(output);
            }, options);

            firstBlock.LinkTo(secondBlock);
            secondBlock.LinkTo(thirdBlock);
            thirdBlock.LinkTo(fourthBlock);

            var populateTasks = Enumerable.Range(1, 10).Select(x => firstBlock.SendAsync(x));
            Task.WhenAll(populateTasks).ContinueWith(x => firstBlock.Complete()).Wait();

            fourthBlock.Completion.Wait();
        }

        private static string GetHashAsString(byte[] bytes)
        {
            var sb = new StringBuilder();
            int i;
            for (i = 0; i < bytes.Length; i++)
            {
                sb.AppendFormat("{0:X2}", bytes[i]);
                if (i % 4 == 3) sb.Append(" ");
            }

            return sb.ToString();
        }
    }
}
Run Code Online (Sandbox Code Playgroud)

结果输出正是我想要的:

10.08.2016 11:03:23: Hash for element #3: 8BA8A86D F25E058E 180F7AA9 1EE996B0 8D721C84 AEE8AA19 0A3F7C44 9FFED481
10.08.2016 11:03:23: Hash for element #1: 8BA8A86D F25E058E 180F7AA9 1EE996B0 8D721C84 AEE8AA19 0A3F7C44 9FFED481
10.08.2016 11:03:23: Hash for element #2: 8BA8A86D F25E058E 180F7AA9 1EE996B0 8D721C84 AEE8AA19 0A3F7C44 9FFED481
10.08.2016 11:03:23: Hash for element #10: C8C87B26 B17A6329 3F6213CD 4F9AFE0D 4F90127B AAE49EB0 7D8C15DF 74F020B1
10.08.2016 11:03:23: Hash for element #8: C8C87B26 B17A6329 3F6213CD 4F9AFE0D 4F90127B AAE49EB0 7D8C15DF 74F020B1
10.08.2016 11:03:23: Hash for element #9: C8C87B26 B17A6329 3F6213CD 4F9AFE0D 4F90127B AAE49EB0 7D8C15DF 74F020B1
10.08.2016 11:03:23: Hash for element #5: C8C87B26 B17A6329 3F6213CD 4F9AFE0D 4F90127B AAE49EB0 7D8C15DF 74F020B1
10.08.2016 11:03:23: Hash for element #7: C8C87B26 B17A6329 3F6213CD 4F9AFE0D 4F90127B AAE49EB0 7D8C15DF 74F020B1
10.08.2016 11:03:23: Hash for element #6: C8C87B26 B17A6329 3F6213CD 4F9AFE0D 4F90127B AAE49EB0 7D8C15DF 74F020B1
10.08.2016 11:03:27: Hash for element #4: FD25E52B FCD8DE81 BD38E11B 13C20B96 09473283 F25346B2 04593B70 E4357BDA
Run Code Online (Sandbox Code Playgroud)