Eri*_*ric 15 java audio javasound output
tl; dr对于未来的读者,使用Java或C#无法(现在)录制实时音频.使用C++,因为它提供了大量的音频api.
我的目标是获得在Windows机器上播放的当前声音,并像图形音频可视化器一样分析声音(获得音量属性和Hz(基数和高音)).当我说当前声音时,我的意思是如果要播放Youtube视频或Spotify歌曲,这个程序会读取该音频输出.我无意播放声音,但实时捕捉它并将其可视化.
在尝试这样做时,我阅读了如何构建音频波形显示,并探讨了如何将音频文件转换为字节数组(一行).这没有用,因为它不会得到当前的声音.我还阅读了如何捕获音频,以及这个java访问声音教程,这些都没有回答我的问题,因为它们都需要加载歌曲文件.
我根本就不理解这一点.我完全无能为力,任何帮助都会受到赞赏.
编辑:我做了一些更多的环顾四周,这个来源的第二个答案让我得出结论:我可以找到所有的音频设备,看看哪一个产生声音.我不知道在那之后该怎么办.
编辑2(再次编辑):从实验和环顾四周,我在下面编写了这段代码.我认为这让我朝着我想要的方向前进,但我不知道如何完成它.
Mixer.Info[] mixers = AudioSystem.getMixerInfo();
for (Mixer.Info mixerInfo : mixers) {
Mixer mixer = AudioSystem.getMixer(mixerInfo);
try {
mixer.open();
Line.Info[] lines = mixer.getTargetLineInfo();
for (Line.Info linfo : lines) {
Line line = AudioSystem.getLine(linfo);
//here I'm opening the line, but I don't know how to grab data
line.open();
}
} catch (LineUnavailableException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
我使用了这个来源:在混音器行中检查音频播放的级别,但我不打算检查所有播放音量的行,我只需要用户默认的混音器,获取该行,并且能够分析数据.
编辑3:我试过了:
//creating a format for getting sound
float sampleRate = 8000;
int sampleSizeInBits = 16;
int channels = 2;
boolean signed = true;
boolean bigEndian = true;
AudioFormat format = new AudioFormat(sampleRate, sampleSizeInBits, channels,
signed, bigEndian);
//creating a line based off of the format
DataLine.Info info = new DataLine.Info( TargetDataLine.class, format);
TargetDataLine line = (TargetDataLine) AudioSystem.getLine(info);
//opening and starting that line
line.open(format);
line.start();
while (conditionIsTrue){
//here, I don't know what to put as the parameters.
//Had I known, I don't know how I would get to analyze the data
line.read();
}
我想我使用上面的代码在正确的道路上,但我不知道如何提取声音并找到bpm,base,treble等.
编辑4:这是一个有趣的读物:Java中的实时低延迟音频处理.这并不涉及哪些类以及如何实际实现它,但它提供了一些见解.
编辑5:@AndrewThompson使用基于链接的这段代码,我能够迭代可用的源和目标行.
Mixer.Info[] mixers = AudioSystem.getMixerInfo();
for (Mixer.Info mixerInfo : mixers) {
Mixer mixer = AudioSystem.getMixer(mixerInfo);
try {
mixer.open();
Line.Info[] sourceLines = mixer.getSourceLineInfo();
Line.Info[] targetLine = mixer.getTargetLineInfo();
for (Line.Info sourceLinfo : sourceLines) {
System.out.println(sourceLinfo );
}
for (Line.Info targetLinefo : targetLine) {
System.out.println(targetLinefo);
}
} catch (LineUnavailableException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
输出如下所示:
interface SourceDataLine supporting 8 audio formats, and buffers of at least 32 bytes
interface Clip supporting 8 audio formats, and buffers of at least 32 bytes
interface SourceDataLine supporting 8 audio formats, and buffers of at least 32 bytes
interface Clip supporting 8 audio formats, and buffers of at least 32 bytes
interface SourceDataLine supporting 8 audio formats, and buffers of at least 32 bytes
interface Clip supporting 8 audio formats, and buffers of at least 32 bytes
HEADPHONE target port
SPEAKER target port
然后我创建了一个方法来获取所有行的声级,如下所示:
private static void getVolumeOfAllLines() {
Mixer.Info[] mixers = AudioSystem.getMixerInfo();
for (Mixer.Info mixerInfo : mixers) {
Mixer mixer = AudioSystem.getMixer(mixerInfo);
try {
mixer.open();
Line.Info[] lines = mixer.getSourceLineInfo();
for (Line.Info linfo : lines) {
DataLine line = (DataLine)AudioSystem.getLine(linfo);
if(line != null)
System.out.println(line.getLevel());
}
} catch (LineUnavailableException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
-in试图找到当前播放的声音,表示音量较高.返回:
-1.0
-1.0
-1.0
-1.0
-1.0
-1.0
没有进展.
新守则:
private static void debug(){
Mixer.Info[] mixers = AudioSystem.getMixerInfo();
for (Mixer.Info mixerInfo : mixers) {
Mixer mixer = AudioSystem.getMixer(mixerInfo);
try {
mixer.open();
Line.Info[] lines = mixer.getTargetLineInfo();
AudioFormat format = new AudioFormat(
AudioFormat.Encoding.PCM_SIGNED,
44100,
16, 2, 4,
44100, false);
AudioFormat[] tdl = AudioSystem.getTargetFormats(AudioFormat.Encoding.PCM_SIGNED, format);
for (Line.Info linfo : lines) {
//Line line = AudioSystem.getLine(linfo);
TargetDataLine line = null;
DataLine.Info info = new DataLine.Info(TargetDataLine.class,
format); // format is an AudioFormat object
if (!AudioSystem.isLineSupported(info))
{
System.out.println("line not supported:" + line );
}
try
{
line = (TargetDataLine) AudioSystem.getLine(info); //error
line.open(format);
System.out.println("line opened:" + line);
line.start();
byte[] buffer = new byte[1024];
int ii = 0;
int numBytesRead = 0;
while (ii++ < 100) {
// Read the next chunk of data from the TargetDataLine.
numBytesRead = line.read(buffer, 0, buffer.length);
System.out.println("\nnumBytesRead:" + numBytesRead);
if (numBytesRead == 0) continue;
// following is a quickie test to see if content is only 0 vals
// present in the data that was read.
for (int i = 0; i < 16; i++)
{
if (buffer[i] != 0)
System.out.print(".");
else
System.out.print("0");
}
}
} catch (LineUnavailableException ex) {
ex.printStackTrace();
//...
}
}
} catch (LineUnavailableException e) {
e.printStackTrace();
}
}
}
Java 教程中有一个很好的示例，可以帮助您从一行中提取 PCM 数据。在标题为使用文件和格式转换器的教程中，标题为“读取声音文件”的部分下有一个代码示例。相关部分是“片段”示例，并由代码标记：
// Here, do something useful with the audio data that's
// now in the audioBytes array...
此时，您可以访问该行的各个字节，并且可以根据声音文件的格式将它们组合成 PCM。还有其他几个stackoverflow问题，它们处理从字节到PCM的细节。
我正在添加一些代码以响应评论。
由于无法转换为 TargetDataLine，从教程中提取的以下内容允许我将一行转换为 TargetDataLine。
AudioFormat format = new AudioFormat(
AudioFormat.Encoding.PCM_SIGNED,
44100,
16, 2, 4,
44100, false);
TargetDataLine line = null;
DataLine.Info info = new DataLine.Info(TargetDataLine.class,
format); // format is an AudioFormat object
if (!AudioSystem.isLineSupported(info))
{
System.out.println("line not supported:" + line );
}
try
{
line = (TargetDataLine) AudioSystem.getLine(info);
line.open(format);
System.out.println("line opened:" + line);
line.start();
byte[] buffer = new byte[1024];
int ii = 0;
int numBytesRead = 0;
while (ii++ < 100) {
// Read the next chunk of data from the TargetDataLine.
numBytesRead = line.read(buffer, 0, buffer.length);
System.out.println("\nnumBytesRead:" + numBytesRead);
if (numBytesRead == 0) continue;
// following is a quickie test to see if content is only 0 vals
// present in the data that was read.
for (int i = 0; i < 16; i++)
{
if (buffer[i] != 0)
System.out.print(".");
else
System.out.print("0");
}
}
} catch (LineUnavailableException ex) {
ex.printStackTrace();
//...
}
}
但我只是使用 CD 质量格式方案抓取一条线，我没有试图找出哪条线具有正在播放的 YouTube 频道的声音。
OP 和我去聊天并继续对此进行破解，但无法找到解决方案。似乎许多其他人也看到了这一点并放弃了。我希望赏金很诱人——这是一个有趣的问题。