use*_*165 7 c# serialization json
我从第三方库获得以下动态对象:
IOrderStore os = ss.GetService<IOrderStore>();
IOrderInfo search = os.Orders.Where(t => t.Number == "test").FirstOrDefault();
IOrder orderFound = os.OpenOrder(search, true);
dynamic order = (dynamic)orderFound;
dynamic requirements = order.Title.Commitments[0].Requirements;
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我需要将其解析为JSON字符串.
我试过这个(使用JSON.net):
string jsonString = JsonConvert.SerializeObject(requirements);
return jsonString;
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但是我得到了一个看似已损坏的JSON字符串,如下所示:
[{ "$ ID": "1"},{ "$ ID": "2"},{ "$ ID": "3"},{ "$ ID": "4"},{ "$ ID" : "5"},{ "$ ID": "6"},{ "$ ID": "7"},{ "$ ID": "8"},{ "$ ID": "9"}, { "$ ID": "10"},{ "$ ID": "11"},{ "$ ID": "12"},{ "$ ID": "13"},{ "$ ID": "14"},{ "$标识": "15"}]
该对象包含多个属性,而不仅仅是'id'.
有什么建议?
Goo*_*ide 11
您是否尝试过使用var代替dynamic?
// Use "var" in the declaration below.
var requirements = order.Title.Commitments[0].Requirements;
string jsonString = JsonConvert.SerializeObject(requirements);
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当你只想反序列化requirements而不用它做任何其他事情时,就没有必要使用它dynamic。
小智 6
尝试使用 Convert.ToString() 作为以下代码将“动态”对象转换为“字符串” -
dynamic order = (dynamic)orderFound;
dynamic requirements = order.Title.Commitments[0].Requirements;
string validString = Convert.ToString(requirements);
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