Raj*_*kar 1 html javascript ajax jquery json
当我尝试从JSON响应中获取值时,我坚持了下来.这是我的代码
码:
$.ajax({
url: 'checkvotes.php',
dataType: "json",
success: function(data) {
// want to fetch UP and DOWN variables from JSON here
}
});
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来自PHP的AJAX响应
{"sample":[{"id":"1","message":"my message","up":"200","down":"34"}]}
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$.ajax({
url: 'checkvotes.php',
dataType: "json",
success: function(data) {
var up = data.sample[0].up;
var down = data.sample[0].down;
}
});
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