如何从AJAX响应中检索JSON变量

Raj*_*kar 1 html javascript ajax jquery json

当我尝试从JSON响应中获取值时,我坚持了下来.这是我的代码

码:

$.ajax({
    url: 'checkvotes.php',
    dataType: "json",
    success: function(data) {
     // want to fetch UP and DOWN variables from JSON here
     }
 });
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来自PHP的AJAX响应

{"sample":[{"id":"1","message":"my message","up":"200","down":"34"}]}
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rek*_*o_t 6

$.ajax({
    url: 'checkvotes.php',
    dataType: "json",
    success: function(data) {
       var up = data.sample[0].up;
       var down = data.sample[0].down;
    }
 });
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