将嵌套的JSON反序列化为C#对象

Question

我从一个看起来像这样的API获得JSON:

{
  "Items": {
    "Item322A": [{
      "prop1": "string",
      "prop2": "string",
      "prop3": 1,
      "prop4": false
    },{
      "prop1": "string",
      "prop2": "string",
      "prop3": 0,
      "prop4": false
    }],
       "Item2B": [{
      "prop1": "string",
      "prop2": "string",
      "prop3": 14,
      "prop4": true
    }]
  },
  "Errors": ["String"]
}

我已经尝试了一些方法来在c#对象中表示这个JSON(这里列出的太多了).我已尝试过列表和词典,这是我最近尝试如何表示它的一个例子:

    private class Response
    {
        public Item Items { get; set; }
        public string[] Errors { get; set; }
    }

    private class Item
    {
        public List<SubItem> SubItems { get; set; }
    }

    private class SubItem
    {
        public List<Info> Infos { get; set; }
    }

    private class Info
    {
        public string Prop1 { get; set; }
        public string Prop2 { get; set; }
        public int Prop3 { get; set; }
        public bool Prop4 { get; set; }
    }

这是我用来反序列化JSON的方法:

    using (var sr = new StringReader(responseJSON))
    using (var jr = new JsonTextReader(sr))
    {
        var serial = new JsonSerializer();
        serial.Formatting = Formatting.Indented;
        var obj = serial.Deserialize<Response>(jr);
    }

obj包含Items和Errors.而Items含有SubItems,但SubItems是null.因此,除了Errors实际上没有反序列化.

它应该很简单,但由于某种原因,我无法弄清楚正确的对象表示

Answer 1

使用此网站进行表示:

http://json2csharp.com/

这样的事可能会对你有所帮助

public class Item322A
{
    public string prop1 { get; set; }
    public string prop2 { get; set; }
    public int prop3 { get; set; }
    public bool prop4 { get; set; }
}

public class Item2B
{
    public string prop1 { get; set; }
    public string prop2 { get; set; }
    public int prop3 { get; set; }
    public bool prop4 { get; set; }
}

public class Items
{
    public List<Item322A> Item322A { get; set; }
    public List<Item2B> Item2B { get; set; }
}

public class jsonObject
{
    public Items Items { get; set; }
    public List<string> Errors { get; set; }
}

以下是反序列化的方法(使用JsonConvert类):

jsonObject ourlisting = JsonConvert.DeserializeObject<jsonObject>(strJSON);

Answer 2

对于"Items"使用Dictionary<string, List<Info>>,即:

class Response
{
    public Dictionary<string, List<Info>> Items { get; set; }
    public string[] Errors { get; set; }
}

class Info
{
    public string Prop1 { get; set; }
    public string Prop2 { get; set; }
    public int Prop3 { get; set; }
    public bool Prop4 { get; set; }
}

这是假设该项目的名称"Item322A",并"Item2B"从响应有所不同响应,并作为字典键读取这些名称.

样品小提琴.

Answer 3

您可以使用，Json.Parse以便您可以查询数据——并且只使用单个模型。

private class Info
{
    public string Prop1 { get; set; }
    public string Prop2 { get; set; }
    public int Prop3 { get; set; }
    public bool Prop4 { get; set; }
}

var result = JObject.Parse(resultContent);   //parses entire stream into JObject, from which you can use to query the bits you need.
var items = result["Items"].Children().ToList();   //Get the sections you need and save as enumerable (will be in the form of JTokens)

List<Info> infoList = new List<Info>();  //init new list to store the objects.

//iterate through the list and match to an object. If Property names don't match -- you could also map the properties individually. Also useful if you need to dig out nested properties.
foreach(var subItem in items){
foreach(JToken result in subItem){
Info info = result.ToObject<Info>();
infoList.add(info);
}}