ygl*_*odt 4 java json hibernate spring-mvc jackson
在一个Hibernate托管实体中考虑这个属性:
@JsonFormat(pattern = "HH:mm")
@Column(name = "start_time")
private java.sql.Time startTime;
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我张贴JSON-object为@RequestBody到一个Spring控制器Jackson应该映射到实体(POJO)的一个实例.
Jackson显然没有设法将时间字符串反序列化为a java.sql.Time,因为我得到了这个例外:
.w.s.m.s.DefaultHandlerExceptionResolver : Failed to read HTTP message:
org.springframework.http.converter.HttpMessageNotReadableException:
Could not read document: Can not construct instance of java.sql.Time,
problem: null
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我该如何指导Jackson理解该怎么做?
解决方案是滚动自己的反序列化器:
import java.io.IOException;
import java.sql.Time;
import com.fasterxml.jackson.core.JsonParser;
import com.fasterxml.jackson.databind.DeserializationContext;
import com.fasterxml.jackson.databind.JsonDeserializer;
public class SqlTimeDeserializer extends JsonDeserializer<Time> {
@Override
public Time deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException {
return Time.valueOf(jp.getValueAsString() + ":00");
}
}
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然后在实体中:
@JsonFormat(pattern = "HH:mm")
@JsonDeserialize(using = SqlTimeDeserializer.class)
@Column(name = "start_time")
private Time startTime;
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