我正在使用RestSharp来POST以下内容:
POST API/storage
Content-Type: application/xml
<StorageDocument xmlns="http://xml.somename.com/schema/somename">
<type>LOCAL</type>
<method>
<uri>file:///path/to/files/</uri>
<read>true</read>
<write>true</write>
<browse>true</browse>
<type>NONE</type>
</method>
<autoDetect>true</autoDetect>
</StorageDocument>
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我的代码:
private void button2_Click(object sender, EventArgs e)
{
var client = new RestClient();
client.BaseUrl = new Uri(baseUrlString);
client.Authenticator = new HttpBasicAuthenticator("admin", "admin");
var request = new RestRequest("API/storage", Method.POST);
request.AddParameter ("Content-Type", "application/xml");
request.RequestFormat = DataFormat.Xml;
string xml =
"<StorageDocument xmlns=\"http://xml.somename.com/schema/somename\">" + Environment.NewLine +
"<type>LOCAL</type>" + Environment.NewLine +
"<method>" + Environment.NewLine +
"<uri>file:///path/to/files/</uri>" + Environment.NewLine +
"<read>true</read>" + Environment.NewLine +
"<write>true</write>" + Environment.NewLine +
"<browse>true</browse>" + Environment.NewLine +
"<type>NONE</type>" + Environment.NewLine +
"</method>" + Environment.NewLine +
"<autoDetect>true</autoDetect>" + Environment.NewLine +
"</StorageDocument>";
request.AddBody(xml);
IRestResponse response = client.Execute(request);
MessageBox.Show(Convert.ToString(response.Content));
}
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当我发布时,我得到"HTTP 415不支持的媒体类型".我尝试了很多东西,但无法弄清问题在哪里.我相信它是使用xml或请求的主体但无法找到解决方案.
有任何想法吗?提前致谢
Art*_*Art 10
对于我这种情况下的某个人来说,这个代码很有用
private void button2_Click(object sender, EventArgs e)
{
var client = new RestClient();
client.BaseUrl = new Uri(baseUrlString);
client.Authenticator = new HttpBasicAuthenticator("admin", "admin");
var request = new RestRequest("API/storage", Method.POST);
string rawXml = "<StorageDocument xmlns=\"http://xml.somename.com/schema/somename\"><type>LOCAL</type><method><uri>file://home/Testuser/storage/</uri><read>true</read><write>true</write><browse>true</browse><type>NONE</type></method><autoDetect>true</autoDetect></StorageDocument>";
request.AddParameter("application/xml", rawXml, ParameterType.RequestBody);
IRestResponse response = client.Execute(request);
MessageBox.Show(Convert.ToString(response.Content));
}
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关键点是使用AddParameter而不是AddBody,这里提到 RestSharp PUT XML,RestSharp将它作为GET发送? 理查德弗里德
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