PHP:生日祝福今日

Question

我已将用户的生日保存在birthday1999-02-26.

我怎样才能检查今天的生日是否如此？

if(date('m-d') == ..?

Answer 1

这个答案应该有效,但这取决于strtotime能够找出数据库的日期格式:

$birthDate = '1999-02-26'; // Read this from the DB instead
$time = strtotime($birthDate);
if(date('m-d') == date('m-d', $time)) {
    // They're the same!
}

Answer 2

if(date('m-d') == substr($birthday,5,5))

添加Tim说的话:

if(date('m-d') == substr($birthday,5,5) or (date('y')%4 <> 0 and substr($birthday,5,5)=='02-29' and date('m-d')=='02-28'))