Es *_*a M 0 php json laravel laravel-5
我已经得到回应,但我不需要这样
{
"status": "200",
"id": 1,
"email": "a@a.a",
"mobile": "",
"source": "",
"source_id": "",
"message": "Bad Request : Already Logged In"
}
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我需要在另一个对象中返回这些数据,例如:
{
{
"status": "200",
}
{
"id": 1,
"email": "a@a.a",
"mobile": "",
"source": "",
"source_id": "",
"message": "Bad Request : Already Logged In"
}
}
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更新(2021 年 2 月 9 日):如果适用,将模型序列化为 JSON 的最佳方法是使用Eloquent 的 API 资源。这在您构建 RESTful API 时特别有用。
使用response()和json()方法。
$data = [
"status" => "200",
"details" => [
"id": 1,
"email": "a@a.a",
"mobile": "",
"source": "",
"source_id": "",
"message": "Bad Request : Already Logged In"
]
];
return response()->json($data);
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这将返回以下 JSON:
{
"status": "200",
"details": {
"id": 1,
"email": "a@a.a",
"mobile": "",
"source": "",
"source_id": "",
"message": "Bad Request : Already Logged In"
}
}
Run Code Online (Sandbox Code Playgroud)
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