如何通过搜索数组找出对象的数组位置？

Question

如果我有这样的数组:

var array1 = 
[
  {"phraseId":"abc",
  "keyword":"bb",
  "posId":1},
  {"phraseId":"def",
  "keyword":"bb",
  "posId":1},
]

如何才能发现具有"def"的phraseId的对象具有第二个位置？

Answer 1

您可以映射对象并仅返回目标字段,然后使用内置indexOf来获取位置:

array1.map(item => item.phraseId).indexOf('def')

Answer 2

使用本机JavaScript findIndex方法.

var array1 = [{
  "phraseId": "abc",
  "keyword": "bb",
  "posId": 1
}, {
  "phraseId": "def",
  "keyword": "bb",
  "posId": 1
}, ];

var pos = array1.findIndex(function(v) {
  // set your condition for finding object             
  return v.phraseId == 'def';
  // add `1` since you want to count from `1`            
}) + 1;

console.log("Position of the object " + pos);

对于较旧的浏览器检查polyfill选项.

具有ES6箭头功能

var array1 = [{
  "phraseId": "abc",
  "keyword": "bb",
  "posId": 1
}, {
  "phraseId": "def",
  "keyword": "bb",
  "posId": 1
}, ];

var pos = array1.findIndex(v => v.phraseId == 'def') + 1;

console.log("Position of the object " + pos);