将所有ng-if设置为false,单击除了单击的项目

Question

我有一个ng-repeat,它有一个按钮,其功能可以在ng-repeat中切换ng-show元素.

类movie_option跨度内部有ng-click=toggleInfo($index):

div additional_info有一个显示或隐藏元素的ng-show.

    <ul ng-cloak="showResult">
        <li class="search_results" ng-repeat="movie in movies | orderBy: '-release_date'  track by $index">
            <div class="movie_info">
                <div class="movie_options">
                    <div class="slide">
                        <span class="movie_option">
                            <span><i class="fa fa-question-circle" aria-hidden="true" ng-click="toggleInfo($index)"></i></span>
                        </span>
                    </div>
                </div>
            </div>
            <div class="additional_info" ng-show="hiddenDiv[$index]">
                {{movie.overview}}
            </div>
        </li>
    </ul>

当用户点击图标时,它会调用此函数:

    $scope.toggleInfo = function (index) {
         $scope.hiddenDiv[index] = !$scope.hiddenDiv[index];
    }

这会从hiddenDiv ng-show切换ng-show状态.这很好用.

我想要做的是将所有hiddenDiv状态设置为false,除了单击的那个,因此只有一个ng-show是真的.

Answer 1

这是一个纯算法问题,与Angular无关.

而不是每个项目都有一个布尔值,只记得应该显示的元素(索引)要简单得多:

<ul ng-cloak="showResult">
    <li class="search_results" ng-repeat="movie in movies | orderBy: '-release_date'  track by $index">
        <div class="movie_info">
            <div class="movie_options">
                <div class="slide">
                    <span class="movie_option">
                        <span><i class="fa fa-question-circle" aria-hidden="true" ng-click="model.displayedIndex = $index"></i></span>
                    </span>
                </div>
            </div>
        </div>
        <div class="additional_info" ng-show="$index === model.displayedIndex">
            {{movie.overview}}
        </div>
    </li>
</ul>

并在你的控制器 $scope.model = {}

小提琴:http://jsfiddle.net/6dkLqgfL/