获取函数的地址 [Swift 3.0]

Question

AnyObject您可以通过函数调用获取函数的地址unsafeAdressOf(object:AnyObject) -> UnsafePointer<void>，但是如何获取函数的地址呢？例如

func foo(){print("hi")}
print(unsafeAdressOf(foo))

不起作用

Answer 1

class Foo {
    func poo(value: Int) {
        print(value)
    }
}
typealias classFunctionType = @convention(thin) (Foo)->(Int)->()

func getSwiftFunctionAddr(_ function: @escaping classFunctionType) -> UnsafeMutableRawPointer {
    return unsafeBitCast(function, to: UnsafeMutableRawPointer.self)
}

let func_addr = getSwiftFunctionAddr(Foo.poo)

print(func_addr)