Service Fabric:ServiceManifest.xml中允许的多种服务类型

Question

我正在尝试在单个exe(ServiceRuntime.RegisterServiceAsync)中注册多个服务结构服务.这支持吗？如果是这样,我将如何配置它们？

例如:ServiceManifest.xml支持ServiceTypes中的多个StatelessServiceType元素:

<?xml version="1.0" encoding="utf-8"?>
<ServiceManifest Name="EchoGatewayPkg"
                 Version="1.0.0"
                 xmlns="http://schemas.microsoft.com/2011/01/fabric"
                 xmlns:xsd="http://www.w3.org/2001/XMLSchema"
                 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <ServiceTypes>
    <StatelessServiceType ServiceTypeName="Service1Type" >
    </StatelessServiceType>

    <StatelessServiceType ServiceTypeName="Service2Type" >
    </StatelessServiceType>
  </ServiceTypes>
...

和ApplicationManifest.xml不支持DefaultServices/Service中的多个StatelessService元素:

<?xml version="1.0" encoding="utf-8"?>
<ApplicationManifest xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" ApplicationTypeName="EchoServiceType" ApplicationTypeVersion="1.0.0" xmlns="http://schemas.microsoft.com/2011/01/fabric">
  <Parameters>
    <Parameter Name="Service1_InstanceCount" DefaultValue="1" />
    <Parameter Name="Service2_InstanceCount" DefaultValue="1" />
  </Parameters>
  <ServiceManifestImport>
    <ServiceManifestRef ServiceManifestName="MyServicePkg" ServiceManifestVersion="1.0.0" />
    <ConfigOverrides />
  </ServiceManifestImport>
  <DefaultServices>
    <Service Name="MyService1">
      <StatelessService ServiceTypeName="Service1Type" InstanceCount="[Service1_InstanceCount]">
        <SingletonPartition />
      </StatelessService>
    </Service>
    <Service Name="MyService2">
      <StatelessService ServiceTypeName="Service2Type" InstanceCount="[Service2_InstanceCount]">
        <SingletonPartition />
      </StatelessService>
    </Service>
  </DefaultServices>
</ApplicationManifest>

因此,这有效地产生了2个进程,并且每个进程的激活上下文都列出了两种默认服务类型(我预计只有一个具有此配置).

欢迎任何建议(关于如何在单个exe中配置多个服务类型)或澄清.

Answer 1

忽略默认服务一秒钟..

是的,这是您获得多种服务类型来共享主机进程的方式.您正在看到2个进程,因为Service Fabric将这两个服务实例放在不同的节点上,每个服务实例都需要一个主机进程.尝试使用InstanceCount =" - 1"创建每个服务,以查看两种类型共享主机进程.

好的,回到默认服务.这本质上是令人困惑的,因为应用程序清单和服务清单仅用于描述类型信息,而不是实例信息.但是,为了在创建应用程序实例时默认创建服务实例,您必须以声明方式指定实例及其参数.所以你在你的例子中看到的默认服务是XML相当于:

PS > New-ServiceFabricService -Stateless -PartitionSchemeSingleton -InstanceCount 1 -ApplicationName fabric:/EchoService -ServiceName fabric:/EchoService/MyService1 -ServiceTypeName Service1Type

PS > New-ServiceFabricService -Stateless -PartitionSchemeSingleton -InstanceCount 1 -ApplicationName fabric:/EchoService -ServiceName fabric:/EchoService/MyService2 -ServiceTypeName Service2Type

因此,在Service元素中包含多个StatelessService元素是没有意义的,因为您要定义要创建的服务实例以及服务实例的类型和版本.

对于后代来说,这是与您发布的服务清单一起使用的注册码:

internal static class Program
{
    private static void Main()
    {
        try
        {
            ServiceRuntime.RegisterServiceAsync("Service1Type",
                context => new Stateless1(context)).GetAwaiter().GetResult();

            ServiceRuntime.RegisterServiceAsync("Service2Type",
                context => new Stateless2(context)).GetAwaiter().GetResult();

            Thread.Sleep(Timeout.Infinite);
        }
        catch (Exception e)
        {
            ServiceEventSource.Current.ServiceHostInitializationFailed(e.ToString());
            throw;
        }
    }
}
}