Zal*_*oza 14 reactjs react-native redux react-redux
我今天说要学习反应和减少,但我无法弄清楚如何在状态改变后迫使组件重新渲染.
这是我的代码:
const store = createStore(loginReducer);
export function logout() { return {type: 'USER_LOGIN'} }
export function logout() { return {type: 'USER_LOGOUT'} }
export function loginReducer(state={isLogged:false}, action) {
switch(action.type) {
case 'USER_LOGIN':
return {isLogged:true};
case 'USER_LOGOUT':
return {isLogged:false};
default:
return state;
}
}
class App extends Component {
lout(){
console.log(store.getState()); //IT SHOW INITIAL STATE
store.dispatch(login());
console.log(store.getState()); //IT SHOWS THAT STATE DID CHANGE
}
////THIS IS THE PROBLEM,
render(){
console.log('rendering')
if(store.getState().isLogged){
return (<MainComponent store={store} />);
}else{
return (
<View style={style.container}>
<Text onPress={this.lout}>
THE FOLLOWING NEVER UPDATE :( !!{store.getState().isLogged?'True':'False'}</Text>
</View>
);
}
}
Run Code Online (Sandbox Code Playgroud)
我可以触发更新的唯一方法是使用
store.subscribe(()=>{this.setState({reload:false})});
Run Code Online (Sandbox Code Playgroud)
在构造函数内部,以便我手动触发组件的更新状态以强制重新呈现.
但我如何链接商店和组件状态?
Dan*_*nny 19
只有在更改状态或道具时,您的组件才会重新渲染.您不是依赖于this.state或this.props,而是直接在渲染函数中获取商店的状态.
相反,您应该使用connect
将应用程序状态映射到组件道具.组件示例:
import React, { PropTypes } from 'react';
import { connect } from 'react-redux';
export class App extends React.Component {
constructor(props, context) {
super(props, context);
}
render() {
return (
<div>
{this.props.isLoggedIn ? 'Logged In' : 'Not Logged In'}
</div>
);
}
}
App.propTypes = {
isLoggedIn: PropTypes.bool.isRequired
};
function mapStateToProps(state, ownProps) {
return {
isLoggedIn: state.isLoggedIn
};
}
export default connect(mapStateToProps)(App);
Run Code Online (Sandbox Code Playgroud)
在这个非常简单的示例中,如果商店的isLoggedIn值发生变化,它将自动更新组件上的相应prop,这将导致它呈现.
我建议您阅读react-redux文档以帮助您入门:http: //redux.js.org/docs/basics/UsageWithReact.html
我最终来到这里是因为我写了一个糟糕的减速器。我有:
const reducer = (state=initialState, action) => {
switch (action.type) {
case 'SET_Q':
return Object.assign(state, { // <- NB no {}!
q: action.data,
})
default:
return state;
}
}
Run Code Online (Sandbox Code Playgroud)
我需要:
const reducer = (state=initialState, action) => {
switch (action.type) {
case 'SET_Q':
return Object.assign({}, state, { // <- NB the {}!
q: action.data,
})
default:
return state;
}
}
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
25169 次 |
最近记录: |