使用 Python 实现神经网络的成本函数（第 5 周 Coursera）

Question

基于 Coursera 机器学习课程，我正在尝试在 python 中实现神经网络的成本函数。有一个与此类似的问题- 有一个可接受的答案 - 但该答案中的代码是用八度写的。不要偷懒，我已经尝试将答案的相关概念适应我的案例，据我所知，我正在正确实现该功能。然而，我输出的成本与预期成本不同，所以我做错了。

这是一个可重现的小示例：

以下链接指向一个.npz可以加载的文件（如下所示）以获取相关数据。"arrays.npz"如果您使用它，请重命名文件。

http://www.filedropper.com/arrays_1

if __name__ == "__main__":

with np.load("arrays.npz") as data:

    thrLayer = data['thrLayer'] # The final layer post activation; you 
    # can derive this final layer, if verification needed, using weights below

    thetaO = data['thetaO'] # The weight array between layers 1 and 2
    thetaT = data['thetaT'] # The weight array between layers 2 and 3

    Ynew = data['Ynew'] # The output array with a 1 in position i and 0s elsewhere

    #class i is the class that the data described by X[i,:] belongs to

    X = data['X'] #Raw data with 1s appended to the first column
    Y = data['Y'] #One dimensional column vector; entry i contains the class of entry i



import numpy as np

m = len(thrLayer)
k = thrLayer.shape[1]
cost = 0

for i in range(m):
    for j in range(k):
        cost += -Ynew[i,j]*np.log(thrLayer[i,j]) - (1 - Ynew[i,j])*np.log(1 - thrLayer[i,j])
print(cost)
cost /= m

'''
Regularized Cost Component
'''

regCost = 0

for i in range(len(thetaO)):
    for j in range(1,len(thetaO[0])):
        regCost += thetaO[i,j]**2

for i in range(len(thetaT)):
    for j in range(1,len(thetaT[0])):
        regCost += thetaT[i,j]**2

regCost *= lam/(2*m) 


print(cost)
print(regCost)

实际上，cost应该是 0.287629，cost + newCost应该是 0.383770。

这是上面问题中贴出的代价函数，供参考：

---

Answer 1

问题是您使用了错误的类标签。计算成本函数时，您需要使用真实值或真实的类标签。

我不确定你的 Ynew 数组是什么，但它不是训练输出。因此，我更改了您的代码以使用 Y 作为类标签来代替 Ynew，并获得了正确的成本。

import numpy as np

with np.load("arrays.npz") as data:

    thrLayer = data['thrLayer'] # The final layer post activation; you
    # can derive this final layer, if verification needed, using weights below

    thetaO = data['thetaO'] # The weight array between layers 1 and 2
    thetaT = data['thetaT'] # The weight array between layers 2 and 3

    Ynew = data['Ynew'] # The output array with a 1 in position i and 0s elsewhere

    #class i is the class that the data described by X[i,:] belongs to

    X = data['X'] #Raw data with 1s appended to the first column
    Y = data['Y'] #One dimensional column vector; entry i contains the class of entry i


m = len(thrLayer)
k = thrLayer.shape[1]
cost = 0

Y_arr = np.zeros(Ynew.shape)
for i in xrange(m):
    Y_arr[i,int(Y[i,0])-1] = 1

for i in range(m):
    for j in range(k):
        cost += -Y_arr[i,j]*np.log(thrLayer[i,j]) - (1 - Y_arr[i,j])*np.log(1 - thrLayer[i,j])
cost /= m

'''
Regularized Cost Component
'''

regCost = 0

for i in range(len(thetaO)):
    for j in range(1,len(thetaO[0])):
        regCost += thetaO[i,j]**2

for i in range(len(thetaT)):
    for j in range(1,len(thetaT[0])):
        regCost += thetaT[i,j]**2
lam=1
regCost *= lam/(2.*m)


print(cost)
print(cost + regCost)

这输出：

0.287629165161
0.383769859091

编辑：修复了整数除法错误，regCost *= lam/(2*m)该错误将 regCost 归零。