在postgres jsonb数组中查找对象的位置

Question

我有一个在value表的jsonb 列中看起来像这样的对象数组:

"west": [
  {"id": "aa92f346-7a93-4443-949b-4eab0badd983", "version": 1},
  {"id": "cd92e346-6b04-3456-050a-5eeb0bddd027", "version": 3}
]

我的目标是根据它们的id和版本从这个数组中删除某些对象,如下所示:

SELECT value::jsonb #- '{west, 1}' FROM game.settings;

但是,它1不应该是硬编码的,而应该等于数组中对象的位置,该位置与我正在寻找的id和版本相匹配(在本例中"id": "cd92e346-6b04-3456-050a-5eeb0bddd027", "version": 3).

我将如何确定此阵列位置并将其传递到我的硬编码1当前保存的位置？

Answer 1

示例数据:

create temp table settings as
select 
    '{"west": [
      {"id": "aa92f346-7a93-4443-949b-4eab0badd983", "version": 1},
      {"id": "cd92e346-6b04-3456-050a-5eeb0bddd027", "version": 3}
    ]}'::jsonb as value;

您可以使用它jsonb_array_elements() with ordinality来确定给定元素的数组位置:

select elem, position
from settings, jsonb_array_elements(value->'west') with ordinality arr(elem, position)
where elem->>'id' = 'cd92e346-6b04-3456-050a-5eeb0bddd027';

                             elem                             | position 
--------------------------------------------------------------+----------
 {"id": "cd92e346-6b04-3456-050a-5eeb0bddd027", "version": 3} |        2
(1 row)

用于position从数组中删除对象:

select value #- array['west', (position- 1)::text] new_value
from settings, jsonb_array_elements(value->'west') with ordinality arr(elem, position)
where elem->>'id' = 'cd92e346-6b04-3456-050a-5eeb0bddd027';

                                new_value                                 
--------------------------------------------------------------------------
 {"west": [{"id": "aa92f346-7a93-4443-949b-4eab0badd983", "version": 1}]}
(1 row)