我有这样的脚本
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Testing Ajax</title>
<script type="text/javascript" src="jquery.js"></script>
</head>
<body>
<a class="test" href="getthis.php">click here</a>
<div class="get"></div>
<script type="text/javascript">
$('.test').click(function(event){
event.preventDefault();
var a = $('body');
$.ajax({
url: "/getthis.php",
dataType: 'text',
success: function(data){
$('.get').append(data.find);
}
});
});
</script>
</body>
</html>
使用此脚本,我尝试获取内容getthis.php
getthis.php只包含这个
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title></title>
</head>
<body>
Olalalalala bebe
</body>
</html>
当我这样做时,我得到结果getthis.php的完整html
我怎么能只获得身体内容？这只是意思."Olalalalala bebe"
有人可以给我解释一下吗？
谢谢...
小智 5
满容易.用另外一层DIV包裹BODY内部会:
$.get(url, {}, function(data){
var data = data.replace('<body', '<body><div id="body"').replace('</body>','</div></body>');
var body = $(data).filter('#body');
//... do what you want with body ...
});