如何在mssql中比较两个xml文件

Question

我有 2 个类型的文件：

@xmlAuthors1 XML =N'
       <Author name="John" surname="Clinton" />
       <Author name="Bill" surname="Skobov" />
       <Author name="John" surname="Lokwood" />;

@xmlAuthors2 XML =N'
       <Author name="Bill" surname="Skobov" />
       <Author name="John" surname="Clinton" />
       <Author name="John" surname="Lokwood" />;

如何发现它们相等？将文件 1 的每一行与文件 2 的每一行进行比较

Answer 1

例如，您可以将它们进行比较：

DECLARE @xmlAuthors1 XML = N'
               <Author name="John" surname="Clinton" />
               <Author name="Bill" surname="Skobov" />
               <Author name="John" surname="Lokwood" />',
        @xmlAuthors2 XML =N'
               <Author name="Bill" surname="Skobov" />
               <Author name="Johns" surname="Clinton" />
               <Author name="John" surname="Lokwood" />'


SELECT *
FROM (
    SELECT  CAST(x1.t.query('.') as nvarchar(max)) as x1,
            CAST(x2.t.query('.') as nvarchar(max)) as x2
    FROM @xmlAuthors1.nodes('/*') as x1(t)
    FULL OUTER JOIN @xmlAuthors2.nodes('/*') as x2(t)
        ON CAST(x1.t.query('.') as nvarchar(max)) = CAST(x2.t.query('.') as nvarchar(max))
) as x
WHERE x1 is null or x2 is null

如果相等则没有输出