在c ++中将字符串转换为整数

Question

您好,我知道它被多次询问,但我没有找到我的具体问题的答案.

我只想转换只包含十进制数字的字符串:

例如256可以,但256a不是.

可以在不检查字符串的情况下完成吗？

谢谢

Answer 1

使我能想到的错误检查可选的最简单方法是:

char *endptr;
int x = strtol(str, &endptr, 0);
int error = (*endptr != '\0');

Answer 2

用C++方式,使用stringstream:

#include <iostream>
#include <string>
#include <sstream>
using namespace std;

int main()
{
    stringstream sstr;
    int a = -1;

    sstr << 256 << 'a';
    sstr >> a;

    if (sstr.failbit)
    {
        cout << "Either no character was extracted, or the character can't represent a proper value." << endl;
    }
    if (sstr.badbit)
    {
        cout << "Error on stream.\n";
    }

    cout << "Extracted number " << a << endl;

    return 0;
}

Answer 3

使用c ++样式的另一种方法:我们检查数字的位数,以了解字符串是否有效:

#include <iostream>
#include <sstream>
#include <string>
#include <cmath>

int main(int argc,char* argv[]) {

    std::string a("256");

    std::istringstream buffer(a);
    int number;
    buffer >> number; // OK conversion is done !
    // Let's now check if the string was valid !
    // Quick way to compute number of digits
    size_t num_of_digits = (size_t)floor( log10( abs( number ) ) ) + 1;
    if (num_of_digits!=a.length()) {
        std::cout << "Not a valid string !" << std::endl;
    }
    else {
        std::cout << "Valid conversion to " << number  << std::endl;
    }

}