use*_*880 5 java arrays string byte concatenation
我正在研究这个问题一段时间,并且在这里没有找到任何关于此的内容,所以我想我会发布我的批评/有用的解决方案.
import java.lang.*;
public class Concat
{
public static void main(String[] args)
{
byte[] buf = new byte[256];
int lastGoodChar=0;
//fill it up for example only
byte[] fillbuf=(new String("hello").getBytes());
for(int i=0;i<fillbuf.length;i++)
buf[i]=fillbuf[i];
//Now remove extra bytes from "buf"
for(int i=0;i<buf.length;i++)
{
int bint = new Byte(buf[i]).intValue();
if(bint == 0)
{
lastGoodChar = i;
break;
}
}
String bufString = new String(buf,0,lastGoodChar);
//Prove that it has been concatenated, 0 if exact match
System.out.println( bufString.compareTo("hello"));
}
}
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aio*_*obe 11
我相信这也是一样的:
String emptyRemoved = "he\u0000llo\u0000".replaceAll("\u0000.*", "");
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