EF7(Core)中同一个表的多个关系

Vei*_*edo 8 .net c# orm entity-framework

我有这样的模特

public class Question
{
    public string Id { get; set; } = Guid.NewGuid().ToString();

    public Answer Answer { get; set; }
    public List<Variant> Variants { get; set; }

    public string CorrectVariantId { get; set; }
    public Variant CorrectVariant { get; set; }
}

public class Variant
{
    public string Id { get; set; } = Guid.NewGuid().ToString();

    public string QuestionId { get; set; }
    public Question Question { get; set; }
}

// mapping

modelBuilder.Entity<Question>()
    .HasOne(q => q.CorrectVariant)
    .WithOne(v => v.Question)
    .HasForeignKey<Question>(q => q.CorrectVariantId);

modelBuilder.Entity<Variant>()
    .HasOne(v => v.Question)
    .WithMany(a => a.Variants)
    .OnDelete(DeleteBehavior.Cascade);
Run Code Online (Sandbox Code Playgroud)

哪个工作完美,直到我升级EF RC1RTM.但现在它抛出: System.InvalidOperationException: Cannot create a relationship between 'Question.Variants' and 'Variant.Question', because there already is a relationship between 'Question.CorrectVariant' and 'Variant.Question'. Navigation properties can only participate in a single relationship.

没有VariantsQuestion模型中删除属性,是否有解决此问题的方法?

Luk*_*uke 16

给出的两个示例已经让我在那里获得了一部分,但我想要一个集合和一个相同对象类型的单个项目,因此我的模型上的表与原始问题中的相同。我试图在下面提供一个适用于 .NET Core 2.2 的简单示例:

public class ParentModel
{
    public int Id { get; set; }

    // Id for single instance navigation property
    public int? ChildModelId { get; set; }

    // Single instance navigation property to ChildTable, identified by ChildModelId property as foreign key
    public virtual ChildModel ChildModel { get; set; }

    // Collection navigation property to ChildTable with identified by ParentId property
    public virtual ICollection<ChildModel> ChildModels { get; set; }
}

public class ChildModel
{
    public int Id { get; set; }

    // Id for ParentModel property back to ParentTable
    public int ParentId { get; set; }

    // Single instance navigation property to ParentTable, identified by ParentId property as foreign key
    public virtual ParentModel ParentModel { get; set; }
}

public class ApplicationDbContext : IdentityDbContext
{
    public ApplicationDbContext(DbContextOptions<ApplicationDbContext> options)
        : base(options)
    {   
    }

    protected override void OnModelCreating(ModelBuilder builder)
    {
        base.OnModelCreating(builder);

        builder.Entity<ParentModel>()
            .ToTable("ParentTable");

        // Configure collection of ChildModels (ParentTable to ChildTable/one-to-many relationship)
        builder.Entity<ParentModel>()
            .HasMany(t => t.ChildModels)
            .WithOne(t => t.ParentModel)
            .HasForeignKey(t => t.ParentId)
            .IsRequired()
            .OnDelete(DeleteBehavior.Cascade);

        builder.Entity<ChildModel>()
            .ToTable("ChildTable");

        // Configure single ChildModel navigation property on ParentModel (one-to-one relationship)
        builder.Entity<ParentModel>()
            .HasOne(t => t.ChildModel)
            .WithOne()
            .HasForeignKey(typeof(ParentModel), nameof(ParentModel.ChildModelId))
            .IsRequired(false)
            .OnDelete(DeleteBehavior.Restrict);
    }
}
Run Code Online (Sandbox Code Playgroud)

避免Navigation properties can only participate in a single relationship.错误的关键是将导航属性配置回父表仅一次。我们ChildModels使用 为 ParentTable上的集合配置它.WithOne(t => t.ParentModel)。然后我们就不用通过调用.WithOne()空来为后续关系配置关系的另一端,因为如果我们再次配置它(例如.WithOne(t => t.ParentModel)),它会出错。

virtual导航属性上的修饰符也允许延迟加载

  • 答对了。谢谢。 (2认同)

Vei*_*edo 11

万一有人会遇到这个问题.这是更优雅的解决方案

public class Question
{
    public Guid Id { get; private set; }
    public IReadOnlyList<Variant> Variants { get; private set; }
    public Guid CorrectVariantId { get; private set; }
    public Guid? AnsweredVariantId { get; private set; }    
    public bool IsAnswerCorrect => CorrectVariantId == AnsweredVariantId;
    public bool IsAnswered => AnsweredVariantId != null;
}

public class Variant
{
    public Guid Id { get; private set; }
    public Guid QuestionId { get; private set; }
    public string HiddenUserLogin { get; private set; }
    public User HiddenUser { get; private set; }
}

// mapping
mb.Entity<Question>()
    .HasMany(q => q.Variants)
    .WithOne()
    .HasForeignKey(nameof(Variant.QuestionId))
    .IsRequired()
    .OnDelete(DeleteBehavior.Cascade);

mb.Entity<Question>()
    .HasOne(typeof(Variant))
    .WithOne()
    .HasForeignKey<Question>(nameof(Question.AnsweredVariantId))
    .IsRequired(false) 
    .OnDelete(DeleteBehavior.Restrict);

// EF creates Unique Index for nullable fields
mb.Entity<Question>()
    .HasIndex(q => q.AnsweredVariantId)
    .IsUnique(false);

// create index instead of FK hence the cyclic dependency between Question and Variant
mb.Entity<Question>()
    .HasIndex(q => q.CorrectVariantId)
    .IsUnique();
Run Code Online (Sandbox Code Playgroud)


Bas*_*ili 5

那是RC1中的错误/不良行为,并且已得到修复。

您应该创建另一个属性,对另一个关系说SecondQuestion。

public class Question
{
  public string Id { get; set; } = Guid.NewGuid().ToString();
  public List<Variant> Variants { get; set; }

  public string CorrectVariantId { get; set; }
  public Variant CorrectVariant { get; set; }
}

public class Variant
{
  public string Id { get; set; } = Guid.NewGuid().ToString();

  public string QuestionId { get; set; }
  public Question Question { get; set; }

  public Question SecondQuestion { get; set; }
}
Run Code Online (Sandbox Code Playgroud)

您的DbContext:

protected override void OnModelCreating(ModelBuilder modelBuilder)
{
  modelBuilder.Entity<Question>()
    .HasOne(q => q.CorrectVariant)
    .WithOne(v => v.SecondQuestion)
    .HasForeignKey<Question>(q => q.CorrectVariantId);

  modelBuilder.Entity<Variant>()
      .HasOne(v => v.Question)
      .WithMany(a => a.Variants).HasForeignKey(x => x.QuestionId).OnDelete(DeleteBehavior.SetNull);

  base.OnModelCreating(modelBuilder);
}
Run Code Online (Sandbox Code Playgroud)

如何使用它:

using (var myDb = new MyDbContext())
{
  var variantFirst = new Variant();
  var variantSecond = new Variant();

  var question = new Question();
  variantFirst.Question = question;

  variantSecond.SecondQuestion = question;

  myDb.Variants.Add(variantFirst);
  myDb.Variants.Add(variantSecond);

  myDb.SaveChanges();
}
Run Code Online (Sandbox Code Playgroud)

  • 还是这样吗?我发现这很可怕,必须定义两个始终指向同一对象的属性,即使如果将SecondQuestion显式设置为与Question不同的值,也可能导致场景崩溃。 (4认同)
  • 某些人的“不良行为”显然是其他人的“不良行为”。:| (2认同)