Python,通过索引将一些列表匹配到列表列表中

Question

所以我有类似的东西:

l1=[1,2,3]
l2=[4,5,6]
l3=[7,8,9]

预期产出是: ls=[[1,4,7],[2,5,8],[3,6,9]]

什么是最核心的方式呢？

Answer 1

使用zip然后列出理解将tuples转换为lists

[list(x) for x in zip(l1, l2, l3)]

结果:

[[1, 4, 7], [2, 5, 8], [3, 6, 9]]

Answer 2

>>> l1=[1,2,3]
>>> l2=[4,5,6]
>>> l3=[7,8,9]
>>> zip(l1, l2, l3)
[(1, 4, 7), (2, 5, 8), (3, 6, 9)]

内置的功能zip将帮助您满足您的需求.

Answer 3

zip 三个清单:

>>> l1 = [1,2,3]
>>> l2 = [4,5,6]
>>> l3 = [7,8,9]
>>> zip(l1,l2,l3)
[(1, 4, 7), (2, 5, 8), (3, 6, 9)]

使用列表理解来投的元组到列表中有一个列表的列表:

>>> [list(i) for i in zip(l1,l2,l3)]
[[1, 4, 7], [2, 5, 8], [3, 6, 9]]