Kyl*_*lan 12 php mysql location cakephp cakephp-3.0
在CakePHP(v3)应用程序中,如何根据传递的lat lng值检索最接近的结果?
我想让它们作为本机CakePHP实体返回,所以像这样:
public function closest($lat, $lng) {
$sightings = //records within given lat lng
$this->set(compact('sightings'));
$this->set('_serialize', ['sightings']);
}
Run Code Online (Sandbox Code Playgroud)
我知道这个SQL有效:
SELECT *,
( 3959 * acos( cos( radians(50.7) ) * cos( radians( latitude ) ) * cos( radians( longitude ) - radians(-1.8) ) + sin( radians(50.7) ) * sin( radians( latitude ) ) ) ) AS distance
FROM sightings
HAVING distance < 10
ORDER BY distance
LIMIT 0 , 20
Run Code Online (Sandbox Code Playgroud)
苦苦挣扎将两者结合起来.
UPDATE
我已经添加
class Sighting extends Entity {
public $_virtual = ['distance'];
//rest of class...
}
Run Code Online (Sandbox Code Playgroud)
所以现在distance
它出现在我的json输出中(正如预期的那样,值为null,但我觉得这是一个步骤).
我在这里看了一下:http://www.mrthun.com/2014/11/26/search-distance-cakephp/这似乎是我想要实现的,所以假设这样的事情:
$latitude = 51.145;
$longitude = -1.45;
$distance = 100;
$this->Sightings->virtualFields
= array('Sightings.distance'
=> '(3959 * acos (cos ( radians('.$latitude.') )
* cos( radians( Sightings.latitude ) )
* cos( radians( Sightings.longitude )
- radians('.$longitude.') )
+ sin ( radians('.$latitude.') )
* sin( radians( Sightings.latitude ) )))');
$sightings = $this->Sightings->find('all', [
'conditions' => ['Sightings.distance <' => $distance]
]);
$this->set(compact('sightings'));
$this->set('_serialize', ['sightings']);
Run Code Online (Sandbox Code Playgroud)
结果是: Column not found: 1054 Unknown column 'Sightings.distance' in 'where clause'
不确定CakePHP v2是否可能与v3相对吗?
ari*_*lia 10
蛋糕3中不再有虚拟字段,但您仍可以为计算字段创建别名
正如@ndm所建议的那样,你最好绑定$latitude
并$longitude
防止SQL注入
$distanceField = '(3959 * acos (cos ( radians(:latitude) )
* cos( radians( Sightings.latitude ) )
* cos( radians( Sightings.longitude )
- radians(:longitude) )
+ sin ( radians(:latitude) )
* sin( radians( Sightings.latitude ) )))';
Run Code Online (Sandbox Code Playgroud)
在哪里使用
$sightings = $this->Sightings->find()
->select([
'distance' => $distanceField
])
->where(["$distanceField < " => $distance])
->bind(':latitude', $latitude, 'float')
->bind(':longitude', $longitude, 'float')
->contain(['Photos', 'Tags']);
Run Code Online (Sandbox Code Playgroud)
使用
$sightings = $this->Sightings->find()
->select([
'distance' => $distanceField
])
->having(['distance < ' => $distance])
->bind(':latitude', $latitude, 'float')
->bind(':longitude', $longitude, 'float')
->contain(['Photos', 'Tags']);
Run Code Online (Sandbox Code Playgroud)
这里需要使用ConnectionManager。
例如:
use Cake\Datasource\ConnectionManager; // Mention this first, preferably on top of the page.
$connection = ConnectionManager::get('default');
$results = $connection
->execute('SELECT * FROM articles WHERE id = :id', ['id' => 1])
->fetchAll('assoc');
Run Code Online (Sandbox Code Playgroud)
您可以尝试以这种方式设置查询。它肯定会起作用。
以此作为参考:
归档时间: |
|
查看次数: |
1815 次 |
最近记录: |